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3 years ago

At about what age does basal metabolic rate begin to gradually decrease?

Chemistry

2 answers:

natulia [17]3 years ago

6 0

This would decrease by 25 hope this helps !!

Leya [2.2K]3 years ago

4 0

Answer:

at age 15 the BMR begin to gradually decrease

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When do plants use the process of cellular respiration

d1i1m1o1n [39]

Answer:

So the answer is every day

Explanation:

Plants respire at all times of the day and night because their cells need a constant energy source to stay alive.

8 0

3 years ago

A silicon atom has an atomic number of 14. What information does the atomic number tell you? (Choose all possible answers)

Bezzdna [24]

Answer:

Silicon atoms have 14 protons.

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Silicon atoms have 14 electrons.

5 0

3 years ago

What would be the colour of litmus in sodium carbonate?<br> will make brainliest

gregori [183]

Answer:

the color of the litmus paper will turn into blue color because sodium carbonate is basic in nature

7 0

3 years ago

What happens when gases change to plasma?

IgorLugansk [536]

Answer:. In the case of neon, it is electrical energy that pulls the electrons off.

explanation-Plasma can be made from a gas if a lot of energy is pushed into the gas. In the case of neon, it is electrical energy that pulls the electrons off. When it is time to become a gas again, just flip the neon light switch off. Without the electricity to energize the atoms, the neon plasma returns to its gaseous state.

8 0

3 years ago

Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K

Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

$MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-$

And the undergoing chemical reaction:

$MgCl_2+2NaF\rightarrow MgF_2+2NaCl$

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

$n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2$

Next, the moles of magnesium chloride consumed by the sodium fluoride:

$n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2$

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

$n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2$

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

$[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M$

$[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M$

Thereby, the reaction quotient is:

$Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}$

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0

3 years ago