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Agata [3.3K]
2 years ago
10

At about what age does basal metabolic rate begin to gradually decrease?

Chemistry
2 answers:
natulia [17]2 years ago
6 0
This would decrease by 25 hope this helps !!
Leya [2.2K]2 years ago
4 0

Answer:

at age 15 the BMR begin to gradually decrease

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Which substance will have the higher melting point,ethanol or ethane?explain
attashe74 [19]

Since hydrogen bonding is a stronger intermolecular force than van der Waals forces, more energy is required to separate the molecules of ethanol than the molecules of ethane. Thus ethanol has a higher melting point than ethane.

6 0
3 years ago
2H2O + 2Na ? 2NaOH + H2 Which of these is a reactant in this chemical reaction?
marin [14]
<h2>Answer:</h2>

Water (H2O) and Sodium (Na) are reactants.

<h2>Explanation:</h2>

2H2O+2Na......2NaOH+H2

In the above reaction the water (H2O) and sodium (Na) are reactants and sodium hydroxide (NaOH) and hydrogen are products.

And this is the single displacement reaction.

8 0
3 years ago
Compounds that are formed when two or more atoms combine to form molecules are called?
madam [21]
Compounds that are formed when two or more atoms combine to form molecules are called Molecular Compounds.
7 0
3 years ago
What is the color red
Anettt [7]

Answer: it's blood

Explanation:

7 0
2 years ago
Determine the number of atoms in 51.0 grams of sodium, Na. (The mass of one mole of sodium is 22.99 g.)
miskamm [114]

Answer:

The answer is

<h3>1.340 × 10²⁴ sodium atoms</h3>

To find the number of atoms of sodium we use the formula

N = n × L

where

n is the number of moles

N is the number of entities

L is Avogadro's constant which is

6.02 \times  {10}^{23}

We need to find the number of moles first

The formula is

n =  \frac{m}{M}

where

M is the molar mass

m is the mass

n is the number of moles

From the question

M = 22.9 g/mol

m = 51.0 g

n =  \frac{51}{22.9}

n = 2.227 moles

So the number of sodium atoms is

N = 2.227 \times 6.02 \times  {10}^{23}

We have the final answer as

<h3>1.340 × 10²⁴ sodium atoms</h3>

Hope this helps you

3 0
3 years ago
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