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Gwar [14]
4 years ago
11

The haber process is typically carried out at a temperature of approximately 500°c. what would happen to the rate of the forward

reaction if the temperature were lowered to 100°c? the reaction rate would
Chemistry
1 answer:
joja [24]4 years ago
8 0
Answer is: t<span>he reaction rate would decrease.

</span><span>The lower is the temperature, the slower the reaction becomes.
</span>The Haber process is <span>procedure for the production of </span>ammonia, in this process <span>atmospheric </span>nitrogen<span> (N</span>₂) is converted to ammonia (NH₃<span>):
</span>N₂ + 3H₂ ⇄ 2NH₃ ΔrH = -92 kJ/mol.
Because this is exothermic reaction (enthalpy is less than zero), a<span>t lower temperatures, the equilibrium is in favor of ammonia, but the reaction doesn't proceed at a detectable rate.</span>
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Which describes the volume of 1 mol of gas at standard temperature and pressure?
Setler79 [48]

Volume of 1  mol of gas at standard temperature and pressure is 22.4 L.

That is using ideal gas equation:

PV = nRT

P=pressure

V=volume

n=number of moles

R=gas constant

T=temperature

at STP,

P=1 atm

T=273K

n=1(given)

Putting all the values in the equation will give,

V= 22.4 L

So, the answer is :

The volume of 1 mol of gas at standard temperature and pressure is 22.4 L.


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At which temperature do the molecules of an ideal gas have 3 times the kinetic energy they have at 32of?
algol [13]

Answer:

  • 820 K

Explanation:

As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.

  • KE α T.

Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

  • First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80

  • Second, convert 0°C to kelvin:

         T (K) = T(°C) + 273.15 K= 273.15 K

Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K

Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.

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