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enyata [817]
3 years ago
15

Which answer is NOT a measure of the amount of matter?

Chemistry
2 answers:
mixer [17]3 years ago
7 0

<u>Answer:</u> STP is not the measure of amount of matter.

<u>Explanation:</u>

Matter is defined as the substance which takes place and has some mass.

For the given options:

Molar mass is defined as the mass which is contained by 1 mole of a substance. It is considered as the unit of matter.

Mole is defined as the mass of substance that has same number of fundamental units, which are present in 12.000 g of ^{12}\textrm{C} atom. It is a unit to measure amount of a substance.

STP is defined as the standard temperature and pressure conditions. The temperature at this condition is taken as 273.15 K  and the pressure at this condition is taken as 1 atm.

Molar volume is defined as the volume of 1 mole of a substance. It is also considered as the unit of matter.

Hence, STP is not the measure of amount of matter.

FinnZ [79.3K]3 years ago
5 0

Answer:

mole

Explanation:

All of the other ones are measuring systems

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4 0
3 years ago
Human blood consists of blood groups A, B, and O. However, there is one more blood group, AB, which contains alleles A and B in
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6 0
3 years ago
Read 2 more answers
When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from
IgorLugansk [536]

The question is incomplete, here is the complete question.

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g S_8.

Answer : The mass of silver sulfide is produced from a mixture is 3.44 grams.

Explanation : Given,

Mass of Ag = 3.0 g

Mass of S_8 = 3.0 g

Molar mass of Ag = 107.8 g/mole

Molar mass of S_8 = 256 g/mole

Molar mass of Ag_2S = 247.8 g/mole

First we have to calculate the moles of Ag and S_8.

\text{ Moles of }Ag=\frac{\text{ Mass of }Ag}{\text{ Molar mass of }Ag}=\frac{3.0}{107.8g/mole}=0.0278moles

\text{ Moles of }S_8=\frac{\text{ Mass of }S_8}{\text{ Molar mass of }S_8}=\frac{3.0g}{256g/mole}=0.0117moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

16Ag(s)+S_8(s)\rightarrow 8Ag_2S(s)

From the balanced reaction we conclude that

As, 16 mole of Ag react with 1 mole of S_8

So, 0.0278 moles of Ag react with \frac{0.0278}{16}=0.00174 moles of S_8

From this we conclude that, S_8 is an excess reagent because the given moles are greater than the required moles and Ag is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag_2S

From the reaction, we conclude that

As, 16 mole of Ag react to give 8 mole of Ag_2S

So, 0.0278 moles of Ag react to give \frac{0.0278}{16}\times 8=0.0139 moles of Ag_2S

Now we have to calculate the mass of Ag_2S

\text{ Mass of }Ag_2S=\text{ Moles of }Ag_2S\times \text{ Molar mass of }Ag_2S

\text{ Mass of }Ag_2S=(0.0139moles)\times (247.8g/mole)=3.44g

Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.

4 0
4 years ago
One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on
gayaneshka [121]

Explanation:

When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.  

This increase in boiling point will be known as elevation in boiling point.

As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.

Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.

Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.

7 0
3 years ago
Methane and sulfur react to produce carbon disulfide (CS₂), a liquid often used in the production of cellophane.
Anestetic [448]

Answer:

9 moles

Explanation:

The balanced chemical equation provided in this question is as follows:

2CH₄ + S₈ → 2CS₂ + 4H₂S

In accordance to the above balanced equation, 1 mole of sulphur (S8) produces 4 moles of hydrogen sulfide (H2S).

Therefore, if 2.25mol of S8 is used, 2.25 × 4 = 9 mol

9 moles of H2S is produced.

6 0
3 years ago
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