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mezya [45]
3 years ago
10

Five pulses are generated every 0.112 s in a tank of water. What is the speed of propagation of the wave if the wavelength of th

e surface wave is 1.20 cm?
Chemistry
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

The answer to the question is

The wave speed is 53.57 cm/s

Explanation:

The speed of a wave is the distance covered by the wave per unit time.

Wave speed is given by

v = f×λ

where v = The velocity of the wave

f = The wave frequency

λ = The wavelength of the wave

the speed v of the wave can also be expressed interms of the period as

v = λ/T

The freuency of the given wave is f = 5/(0.112 s) = 44.64 Hz and the wavelength is λ = 1.20 cm

Therefore the speed of the wave = 44.64 Hz × 1.20 cm = 53.57 cm/s

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How many moles are there in 1.20 x 1025 particles of helium?
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Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0
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