<span>523 grams
First, calculate the molar mass of CH3OH
Atomic weight of carbon = 12.0107
Atomic weight of hydrogen = 1.00794
Atomic weight of oxygen = 15.999
Molar mass of CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146
Now determine how many moles you have by dividing the number of atoms by avogadro's number
moles = 9.83 x 10^24 / 6.0221409 x 10^23 = 16.3231
Now multiply the number of moles by the molar mass
16.3231 * 32.04146 = 523.0159557
Since we only have 3 significant figures, round the result to 3 significant figures.
523.0159557 grams = 523 grams</span>
Answer:
B. Yes, because the mass of all the products of burning is equal to the mass
of the reactants (wood and oxygen gas).
Explanation:
good luck
NaHCO3 is a product of a strong base and a weak acid reaction. Thus it has weak basic properties.
HCO3- ion is actually amphoteric, which means it can act as a base or an acid. But it is weaker than a strong acid or a strong base.
<span>HCO3- is amphoteric meaning it acts both as a B.L. Acid and a B.L. Base.. which is why it's used to neutralize both acid and base spills in the lab.</span>
The correct answer is c, it’s evaporating there for it’s a chemical change
Here is the full question:
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes? (Round your answer to three decimal places.
Answer:
0.046 %
Explanation:
The rate-in;
= 0.8
The rate-out
= 
= 
We can say that:
where;
A(0)= 0.2% × 6000
A(0)= 0.002 × 6000
A(0)= 12
Integration of the above linear equation =
so we have:
![\frac{d}{dt}[e^{\frac{1}{3}t}A]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5Be%5E%7B%5Cfrac%7B1%7D%7B3%7Dt%7DA%5D)
∴ 
Since A(0) = 12
Then;
Hence;
∴ the concentration at 10 minutes is ;
= 
%
= 0.0456667 %
= 0.046% to three decimal places
