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Scilla [17]
3 years ago
13

Water changes from a liquid to a gas in the process of evaporation. true or false

Chemistry
2 answers:
Aleks04 [339]3 years ago
6 0

this is a very true statement


Umnica [9.8K]3 years ago
4 0
This it true because in the triangle of the transformation from solid, liquid, and gas
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Which of the following measurements (of different masses) is the most precise? A 6.2000g B 6.000000g C 6.24400g D 6.24444g
babymother [125]

Answer:

B

Explanation:

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3 years ago
8. What is the chemical formula for sulfuric acid? Explain in great detail.
-Dominant- [34]

The chemical formula for sulfuric acid is H2SO4.

Detailed explanation:

This means that there are 2 atoms of hydrogen, 1 atom of sulfur, and 4 atoms of oxygen in a single molecule. Hope this helps!

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2 years ago
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Which of the following gases is not an important component of soil?
Scilla [17]

Sorry my friend you don't have options so It can't be answered...

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2 years ago
3.0 mL of 0.02 M Fe(NO3)3 solution is mixed with 3.0 mL of 0.002 M NaNCS and diluted to the mark with HNO3 in 10 mL volumetric f
Stella [2.4K]

Answer:

The K_c for [Fe(NCS)]^{2+} formation is 5.7\times 10^2.

Explanation:

Moles=Concentration\times Volume (L)

Fe(NO_3)_3(aq)\rightarrow Fe^{3+}(aq)+3NO_3^{-}(aq)

[Fe(NO_3)_3]=0.02 M=[Fe^{3+}]

Concentration of ferric ion = [Fe^{3+}]=0.02 M

Volume of ferric solution = 3.0 mL = 0.003 L

Moles of ferric ion  =0.02 M\times 0.003 L

1 mL = 0.001 L

NaNCS(aq)\rightarrow Na^+(aq)+NCS^-(aq)

[NaNCS]=0.002 M=[NCS^-]

Concentration of NCS^- ion = [NCS^{-}]=0.002 M

Volume of NCS^- ion solution = 3.0 mL = 0.003 L

Moles of NCS^- ion= 0.002 M\times 0.003 L

Volume of nitric acid solution = 10 mL = 0.010 L

After mixing all the solution the concentration of ferric ion and NCS^- ion will change

Total volume of solution = 0.003 L + 0.003 L + 0.010 L = 0.016 L

Initial concentration of ferric ion before reaching equilibrium :

= \frac{0.02 M\times 0.003 L}{0.016 L}=0.00375 M

Initial concentration of NCS^- ion before reaching equilibrium :

= \frac{0.002 M\times 0.003 L}{0.016 L}=0.000375 M

Fe^{3+}+NCS^-\rightleftharpoons [Fe(NCS)]^{2+}

Initially:

0.00375 M    0.000375 M       0

At equilibrium :

(0.00375-x)   (0.000375-x)       x

Equilibrium concentration of [Fe(NCS)]^{2+}=x=2.5\times 10^{-4} M

The expression of equilibrium constant for formation [Fe(NCS)]^{2+} is given by :

K_c=\frac{[[Fe(NCS)]^{2+}]}{[Fe^{3+}][NCS^-]}

K_c=\frac{x}{(0.00375-x)\times (0.000375-x)}

K_c=\frac{2.5\times 10^{-4} }{(0.00375-2.5\times 10^{-4})\times (0.000375-2.5\times 10^{-4})}

K_c=5.7\times 10^2

The K_c for [Fe(NCS)]^{2+} formation is 5.7\times 10^2.

5 0
3 years ago
Based on the passage, what can be concluded about the ability of humans to see Xrays and gamma rays?
4vir4ik [10]

Answer:

B. Humans can see X-rays and gamma rays.

Explanation:

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3 0
2 years ago
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