Spontaneous Radio activity
Answer:
The power dissipated is reduced by a factor of 2
Explanation:
The power dissipated by a resistor is given by:
![P=I^2 R](https://tex.z-dn.net/?f=P%3DI%5E2%20R)
where
I is the current
R is the resistance
by using Ohm's law,
, we can rewrite the previous equation in terms of the voltage applied across the resistor (V):
![P=(\frac{V}{R})^2R=\frac{V^2}{R}](https://tex.z-dn.net/?f=P%3D%28%5Cfrac%7BV%7D%7BR%7D%29%5E2R%3D%5Cfrac%7BV%5E2%7D%7BR%7D)
In this problem, the resistance of the element is doubled, while the voltage is kept constant. So we have
while V remains the same; substituting into the formula, we have:
![P'=\frac{V^2}{2R}=\frac{1}{2}\frac{V^2}{R}=\frac{P}{2}](https://tex.z-dn.net/?f=P%27%3D%5Cfrac%7BV%5E2%7D%7B2R%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7BV%5E2%7D%7BR%7D%3D%5Cfrac%7BP%7D%7B2%7D)
so, the power dissipated is reduced by a factor 2.
02 is oxygen gas , having 2 particles of O, whereas F2 is Fluorine gas having two particles of F.
Answer:
600 J
Explanation:
The formula to find the kinetic energy of an object is
- m = mass in kg
- V = velocity in m/s
- KE is measured in Joules just as all other forms of energy.
Now, let's plug in the variables we're given and simplify.
Thus, the answer is 600 Joules.
K.E= 50,000 Joules= 1/2mv^2=1/2x1,000kgxv^2
v^2=2x50,000 Joules/1,000kg = 100m^2/v62
v=10m/s
The speed of the car is 10 m/s