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lions [1.4K]
3 years ago
6

5.17 System of blocks acceler-ates. A experiences friction. drawaA :aB​

Physics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

A block is pulled along a horizontal surface (with friction) by a con- stant force with magnitude Fx, and the acceleration ax is measured. The experiment is repeated ...

Explanation:

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A 3.4kg aluminium ball has an apparent mass of 2.10kg when submerged in a particular liquid. Calculate the density of the liquid
Shalnov [3]

Answer:

1083.3kg/m ³

Explanation:

Given parameters:

Mass of aluminium ball = 3.4kg

Apparent mass of ball = 2.1kg

Unknown:

Density of the liquid = ?

Solution:

Density is is the mass per unit volume of any give substance;

         Density = \frac{mass}{volume}

     Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;

     

   Pl = \frac{Ml}{Vl}

   Pl = density of liquid

   Ml = mass of liquid

   Vl = volume of liquid

 Mass of liquid = Mal - Mapparent

       Mal = mass of aluminium

The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;

              Ml = Pl x Vl

      Val = Vl

      Val volume of aluminium

      Vl = volume of liquid

            ****

        Pal = \frac{Mal}{Val}

       Val = \frac{Mal}{Pal}

       Val = volume of aluminium

       Mal = mass of aluminium

       Pal = density of aluminium

   *****

      Since the Val = Vl

          Ml = Pl x \frac{Mal}{Pal}

    Since

          Ml = Mal - Mapparent

                Mal - Mapparent  = Pl  x \frac{Mal}{Pal}

Pal = density of aluminium = 2712 kg/m ³

             3.4 - 2.1 = Pl x \frac{3.4}{2712}

                 1.3 = Pl x 0.00123

                    Pl = 1083.3kg/m ³

       

5 0
4 years ago
11) The total conversion of 2.50 kilogram of the
Elanso [62]

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

⇒1.41 × 10³⁰ MeV

If you want to learn more about mass-energy conversions then you can check out this link:

https://brainly.in/question/9760064

3 0
2 years ago
Read 2 more answers
When a man stands on a bathroom scale here on Earth, it reads 640 N . Assume each planet to be a perfect sphere with the followi
noname [10]

Answer:

242.19702 N

578.46718 N

681.02785 N

Explanation:

M = Mass of the corresponding planet

r = Radius of the corresponding planet

g = Acceleration due to gravity = 9.81 m/s²

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Mass of person

m=\frac{W}{g}\\\Rightarrow m=\frac{640}{9.81}=65.23955\ kg

Mass is the property of an object, it is constant irrespective of the forces acting on it so the mass of the person on each planet would be the same.

Gravitational force on Mars

F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 6.419\times 10^{23}\times 65.23955}{(3.396\times 10^{6})^2}\\\Rightarrow F=242.19702\ N

Magnitude of the gravitational force Mars would exert on the man if he stood on its surface is 242.19702 N

Gravitational force on Venus

F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 4.869\times 10^{24}\times 65.23955}{(6.052\times 10^{6})^2}\\\Rightarrow F=578.46718\ N

Magnitude of the gravitational force Venus would exert on the man if he stood on its surface is 578.46718 N

Gravitational force on Saturn

F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 5.685\times 10^{26}\times 65.23955}{(6.027\times 10^{7})^2}\\\Rightarrow F=681.02785\ N

Magnitude of the gravitational force Saturn would exert on the man if he stood on its surface is 681.02785 N

6 0
4 years ago
A car is traveling at 15m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0s . the coefficient o
iren2701 [21]

Answer:

the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

Explanation:

Given that;

final velocity v = 0

initial velocity u = 15m/s

time taken t = 4 s

acceleration  a = ?

from the equation of motion        

v   =   u   +   at

we substitute

0 = 15 + a × 4

acceleration a = -15/4 =  - 3.75 m/s²    

the negative sign tells us that its a  deacceleration so the sign can be ignored.

Deacceleration due to friction a = μ × g

we substitute

3.75 = μ × 9.8    

μ = 3.75 / 9.8 = 0.3826 ≈ 0.38

Therefore the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

8 0
3 years ago
THIS IS DUE TOMORROW! WILL GIVE BRAINLIEST!!
jonny [76]

Answer:

With distance from the ridge crest, the sediments and crust get thicker. This also supports the idea that the youngest rocks are on the ridge axis and that the rocks get older with distance away from the ridge (Figure below). Something causes the seafloor to be created at the ridge crest.

6 0
3 years ago
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