Answer:
1083.3kg/m
³
Explanation:
Given parameters:
Mass of aluminium ball = 3.4kg
Apparent mass of ball = 2.1kg
Unknown:
Density of the liquid = ?
Solution:
Density is is the mass per unit volume of any give substance;
Density = 
Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;
Pl = 
Pl = density of liquid
Ml = mass of liquid
Vl = volume of liquid
Mass of liquid = Mal - Mapparent
Mal = mass of aluminium
The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;
Ml = Pl x Vl
Val = Vl
Val volume of aluminium
Vl = volume of liquid
****
Pal = 
Val = 
Val = volume of aluminium
Mal = mass of aluminium
Pal = density of aluminium
*****
Since the Val = Vl
Ml = Pl x
Since
Ml = Mal - Mapparent
Mal - Mapparent = Pl x
Pal = density of aluminium = 2712 kg/m
³
3.4 - 2.1 = Pl x 
1.3 = Pl x 0.00123
Pl = 1083.3kg/m
³
1.41 × 10³⁰ MeV
As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).
Given mass = 2.5 kgs
∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J
As our answer is in joules so we have to convert it into mega electron volt(MeV)
1 J = 6.242 × 10¹² MeV
⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV
⇒1.41 × 10³⁰ MeV
If you want to learn more about mass-energy conversions then you can check out this link:
https://brainly.in/question/9760064
Answer:
242.19702 N
578.46718 N
681.02785 N
Explanation:
M = Mass of the corresponding planet
r = Radius of the corresponding planet
g = Acceleration due to gravity = 9.81 m/s²
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
Mass of person
Mass is the property of an object, it is constant irrespective of the forces acting on it so the mass of the person on each planet would be the same.
Gravitational force on Mars
Magnitude of the gravitational force Mars would exert on the man if he stood on its surface is 242.19702 N
Gravitational force on Venus
Magnitude of the gravitational force Venus would exert on the man if he stood on its surface is 578.46718 N
Gravitational force on Saturn
Magnitude of the gravitational force Saturn would exert on the man if he stood on its surface is 681.02785 N
Answer:
the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Explanation:
Given that;
final velocity v = 0
initial velocity u = 15m/s
time taken t = 4 s
acceleration a = ?
from the equation of motion
v = u + at
we substitute
0 = 15 + a × 4
acceleration a = -15/4 = - 3.75 m/s²
the negative sign tells us that its a deacceleration so the sign can be ignored.
Deacceleration due to friction a = μ × g
we substitute
3.75 = μ × 9.8
μ = 3.75 / 9.8 = 0.3826 ≈ 0.38
Therefore the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Answer:
With distance from the ridge crest, the sediments and crust get thicker. This also supports the idea that the youngest rocks are on the ridge axis and that the rocks get older with distance away from the ridge (Figure below). Something causes the seafloor to be created at the ridge crest.
