The solution is impossible because when the apply the right equation for electrical power, the current obtained is 0.83 A and not 11.4 A
<h3>What is power?</h3>
This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = voltage (V) × current (I)
P = IV
With above formula, we can obtain the current drawn by the bulb. Details below
<h3>How to determine the current flowing in the circuit</h3>
From the question given, the following data were obtained:
- Power (P) = 100 W
- Voltage (V) = 120 V
- Current (I) =?
P = IV
Divide both sides by V
I = P / V
I = 100 / 120
I = 0.83 A
Thus, we can see that the current drawn by the bulb is 0.83 A and not 11.4 A
From the above, we can see clearly why the inquisitive physics student' calculation is wrong.
Learn more about electrical power:
brainly.com/question/64224
#SPJ4
Answer:
18.9 <em>N or </em><em>19</em><em> N </em>rounded
Explanation:
m = 0.145 kg
a = 130 m/s^2
F = ma = (0.145 kg)(130 m/s^2) = 18.9 <em>N</em>
Answer:
5.23 C
Explanation:
The current in the wire is given by I = ε/R where ε = induced emf in the wire and R = resistance of wire.
Now, ε = -ΔΦ/Δt where ΔΦ = change in magnetic flux = AΔB and A = area of loop and ΔB = change in magnetic field intensity = B₂ - B₁
B₁ = 0.670 T and B₂ = 0 T
ΔB = B₂ - B₁ = 0 - 0.670 T = - 0.670 T
A = πD²/4 where D = diameter of circular loop = 13.2 cm = 0.132 m
A = π(0.132 m)²/4 = 0.01368 m² = `1.368 × 10⁻² m²
ε = -ΔΦ/Δt = -AΔB/Δt = -1.368 × 10⁻² m² × (-0.670 T)/Δt= 0.9166 × 10⁻² Tm²/Δt
Now, the resistance R of the circular wire R = ρl/A' where ρ = resistivity of copper wire = 1.68 x 10⁻⁸ Ω.m, l = length of wire = πD and A' = cross-sectional area of wire = πd²/4 where d = diameter of wire = 2.25 mm = 2.25 × 10⁻³ m
R = ρl/A' = 1.68 x 10⁻⁸ Ω.m × π × 0.132 m÷π(2.25 × 10⁻³ m)²/4 = 0.88704/5.0625 = 0.1752 × 10⁻² Ω = 1.752 × 10⁻³ Ω
So, I = ε/R = 0.9166 × 10⁻² Tm²/Δt1.752 × 10⁻³ Ω
IΔt = 0.9166 × 10⁻² Tm²/1.752 × 10⁻³ Ω = 0.5232 × 10 C
Since ΔQ = It = 5.232 C ≅ 5.23 C
So the charge is 5.23 C