Molten Mattet Seeps through the crust and forms new land.
Time period remains the same in both the experiment as change in amplitude does not affect time period.
What are the factors on which time period depends in SHM?
Time period is given by:
where,
T = time period
m = mass
k = spring constant
In a straightforward harmonic motion, we see from the preceding formula that the time period depends only on the object's mass and spring constant (SHM). The time period will adjust to any variations in the object's mass or the spring constant.
What is Spring Constant?
A spring's "spring constant" is a property that quantifies the relationship between the force acting on the spring and the displacement it produces. In other words, it characterises a spring's stiffness and the extent of its range of motion.
Learn more about SHM here:
brainly.com/question/20885248
#SPJ4
I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.
Answer:
1. 200 metres West
2. Dividing distance by time
3. Speed was unchanged
4. 1800 metres
5. 15 seconds
Explanation:
Running 500 metres West puts you 500 Metres west from the start. Then running 300 metres east puts you 200metres from where you started.
Since displacement is the distance you are from your original position 200 Metres West is the answer
2. Distance = Speed x Time
Rearrange that to get Speed = Distance / Time
3. Acceleration is when the rate of increase or decrease of speed or the direction is changing. When the speed or sirection dont change acceleration is 0
4. Distance = Speed x Time
60 x 30 = 1800 metres
5. Time = Distance / Speed
300 / 20 = 15 seconds
Answer:
19.99 kg m²/s
Explanation:
Angular Momentum (L) is defined as the product of the moment of Inertia (I) and angular velocity (w)
L = m r × v.
r and v are perpendicular to each other,
where r = lsinθ.
l = 2.4 m
θ= 34°
g = 9.8 m/s² and m = 5 kg
resolving using newtons second law in the vertical and horizontal components.
T cos θ − m g = 0
T sin θ − mw² lsin θ = 0
where T is the force with which the wire acts on the bob
w = √g / lcosθ
= √ 9.8 / 2.4 ×cos 34
= 2.2193 rad/s
the angular momentum L = mr× v
= mw (lsin θ)²
= 5 × 2.2193 (2.4 ×sin 34°)²
=19.99 kg m²/s
