if a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?

Physics

1 answer:

djyliett [7]2 years ago

4 0

Answer:

0.1 N

Explanation:

Considering the relationship between force,

spring constant and extension as defined by Hook's law

The force F=xk as from Hooke's law where F is the force of the spring, k is spring constant and x is extension or compression. Substituting 2 N/m for k and 5cm which is equivalent to 0.05 m for extention x then the force will be

F=2*0.05=0.1 N

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