if a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?
1 answer:
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Answer:
m₁ v = m₂ v
Explanation:
Let's define a system formed by the two objects, for this system the forces during the crash are internal, action and reaction, so that the memento is conserved,
Let's write the initial moment, before shock
p₀ = m₁ v + 0
Final after crash
= 0+ m₂ v
How the moment is preserved
p₀ =
m₁ v = m₂ v
It tells us that peer speed
m₁ = m₂
Since the two masses are the same, it shows that the moment is preserved in this collision.
The kinetic energy is
Initial
K₀ = ½ m₁ v² + 0
Final
= 0 + ½ m₂ v²
K₀ =
½ m₁ v² = ½ m₂ v²
m₁ = m₂
which is true because it indicates that the objects are the same.