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MariettaO [177]
3 years ago
15

Two friends of different masses are on the playground. They are playing on the seesaw and are able to balance it even though the

ir masses are different. show answer No Attempt How are they able to balance on the seesaw? They are able to balance their individual energies. All of these. Their densities are the same. They are able to balance forces due to gravity. They are able to balance their individual momenta. They are able to balance torques due to gravity.
Physics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

They are able to balance torques due to gravity.

F_1 L_1 = F_2L_2

Explanation:

When two friends of different masses will balance themselves on see saw then at equilibrium position the see saw will remain horizontal

This condition will be torque equilibrium position where the see saw will not rotate

Here we can say

F_1 L_1 = F_2L_2

here we know that force is due to weight of two friends

and their positions are different with respect to the lever about which see saw is rotating

since both friends are of different weight so they will balance themselves are different positions as per above equation

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(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

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- the buoyant force, equal to B=m_w g (m_w=mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

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(b) 1.98\cdot 10^{-4} m^3

If the rock is completely submerged, the volume of the rock corresponds to the volume of water  displaced.

The volume of water displaced is given by

V_w = \frac{m_w}{\rho_w}

where

m_w = 198 g = 0.198 kg is the mass of the water displaced

\rho_w = 1000 kg/m^3 is the density of the water

Substituting,

V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3

And so this is also the volume of the rock.

(c) 2727 kg/m^3

The average density of the rock is given by

\rho = \frac{m}{V}

where

m = 540 g = 0.540 kg is the mass of the rock

V=1.98\cdot 10^{-4} m^3 is its volume

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\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3

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In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

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Answer:

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Explanation:

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