Incomplete question.The complete question is here
A rock is thrown downward into a well that is 9.00m deep.
If the splash is heard 1.17 seconds later, what was the initial speed of the rock? Take the speed of sound in the air to be 343 m/s.
Answer:
v₀= 2.263 m/s....(initial speed)
Explanation:
Given Data
well is = 9.00m deep
time=1.17 seconds
speed of sound =343 m/s
To find
Speed of rock=?
Solution
as
gravity=9.8 m/s²
Time the splash reaches=d/v = 9/343= 0.026239s
Rock fall time= 1.17-0.0262= 1.1438s
thrown downward:
h=h₀-v₀t+1/2gt²...................eq(i)
Where h=0m
h₀=9m
t=1.1438s
g=-9.8m/s²
put the values in eq(i)
0= 9-(v₀×1.1438)+{1/2(-9.8)×(1.1438)²}
1.1438v₀= 2.589
v₀= 2.263 m/s....(initial speed)
Traditional is the old way of doing stuff, Command is a system ruled by one person, Market is having buyers and sellers make economic decisions
Answer:
200 meters+1000 meters+800 meters=2000 meters or 2km
Explanation:
1km=1000m
Answer:
It is the angle of refraction in glass for which the angle of incidence in air is 90°.
Explanation:
When light is refracted, the sine of the angle changes in proportion to the refractive index. When the light is 90 degrees, the sine is zero, and zero is still zero on the other side. So nothing changes.