From the calculations, the heat of the reaction is 44.4 kJ/mol.
<h3>What is the enthalpy of reaction?</h3>
The enthalpy of reaction refers to the amount of heat that is absorbed or evolved in a reaction.
Number of moles of NaOH = 1.1 g /40 g/mol = 0.0275 moles
Mass of the water = 22.1 mL or 22.1 g
Given that;
H= mcdT
H = 22.1 g *4.184 * (31.4 - 18.2)
H = 1221 J or 1.221kJ
ΔH rxn = -(1.221kJ)/0.0275 moles
ΔH rxn = 44.4 kJ/mol
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Explanation:
The given data is as follows.
Moles of propylene = 100 moles, = 100 J/mol K
= 300 K, = 800 K
= 2 , = 0.02
Therefore, the assumptions will be as follows.
- The given system is very well insulated.
- The work is done on the system because the given process is a compression process.
- Assume that there is no friction so, work done on the system is equal to the heat energy liberated.
= W
Putting the given values into the above formula as follows.
= W
W =
= J
= 5 MJ
Hence, this shows that a minimum of 5 MJ work needs to be done.
Since, work is very less. Hence, it will not compress the given system to 800 K and 0.02 .
Answer:
Li to Zn2+
Explanation:
Because oxidation number of Li changes from 0 to 2+ it means that Li has lost two electrons and oxidation number of Zn2+ changes to Zn which means Zn received two electrons.
0.5 litres contain 1.1 moles
therefore 1 litre will have= 1*1.1/0.5
molarity=2.2M