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2 years ago

Can someone help me out

Mathematics

1 answer:

Sophie [7]2 years ago

6 0

Firstly, you want to multiply (f^4)^2. $\frac{2*f^8*f^2}{8f^{12}}$

Next, multiply everything on the numerator. $\frac{2f^{10}}{8f^{12}}$

Next, divide. $\frac{2f^{10}}{8f^{12}}=\frac{1}{4} f^{-2}$

Now remember that f^-2 = (1/f^2), so just convert the negative powered exponent to that, and your answer will be $\frac{1}{4f^2}$

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Which stament is true

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Answer:

i think it A

Step-by-step explanation:

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3 years ago

Read 2 more answers

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

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Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

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3 years ago

What is the measure of angle A, in degrees?

juin [17]

96°.

Since sides AB and AC ane equal, that means that angle B is equal to angle C. The measurement of all the angles of a triangle always equals 180°, so if you add angles B and C, you should get 84° and then you should be able to find angle A. Subtract 84° from 180° and you should get 96°.

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3 years ago

What is the standard form of the equation given the slope of: - 3/5 and y-intercept 5

AlladinOne [14]

Answer:

y= -3/5x+5

Step-by-step explanation:

3 0

3 years ago

here's a graph of a linear function. write the equation that describes that function. express it in slope intercept form. HELP!

IRISSAK [1]

Answer:

$y=\frac{3}{4}x+2$

Step-by-step explanation:

So when you express a linear function in slope-intercept form it's given in the form of y=mx+b, where m is the slope, and b is the y-intercept. This is because as x increases by 1, the y-value will increase by m (because multiplication), and since the slope is defined as rise/run, the rise will be m, and run will be 1, giving you a slope of m/1 or m. The reason b is the y-intercept, is because whenever the linear function crosses the y-axis, the x-value will always be 0. Meaning that mx will be 0 because m * 0 will equal 0... and that leaves b by it self, so b will determine the y-intercept.

So if you look at the graph, the linear function crosses the y-axis as (0, 2) so the value of b will be 2. This gives you the equation y=mx+2.

Now to calculate the slope, we can take any two points and see how much the rise was and how much the run was. It can also be more formally defined in the equation: $y=\frac{y_2-y_1}{x_2-x_1}$ . So let's take the points (0, 2) and (8, 8). As you can see the x-value increases by 8 or "ran" by 8, and the y-value increased by 6. So the rise over run in this case is 6/8 which can simplified as 3/4. That is the slope. This gives you the complete equation of: $y=\frac{3}{4}x+2$

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1 year ago