All categories

3 years ago

Acid rain has a higher than normal pH. a. True b. False

1 answer:

4 0

False. Since acids are proton donors and pH=-log[H⁺], acids lower the pH of the solution that they are put into. Therefore acid rain will have a lower pH than normal.
I hope this helps.

You might be interested in

PLEASE HELP, WILL GIVE BRAINLIEST!

Over [174]

Hi,
The purpose of the burning splint is to provide activation energy.

5 0

3 years ago

Please help me out here please

zepelin [54]

I would say G sorry if it’s not right

3 0

3 years ago

Read 2 more answers

4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),

Elina [12.6K]

Answer : The value of new volume is, 50.0 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure at STP = 1 atm

$P_2$ = final pressure = 4.00 atm

$V_1$ = initial volume at STP = 200.0 mL

$V_2$ = final volume = ?

Now put all the given values in the above equation, we get:

$1atm\times 200.0mL=4.00atm\times V_2$

$V_2=50.0mL$

Therefore, the value of new volume is, 50.0 mL

6 0

3 years ago

How many grams of Cl are in 525g of CaCl2

Tema [17]

First we determine the moles CaCl2 present:

525g / (110.9g/mole) = 4.73 moles CaCl2 present

Based on stoichiometry, there are 2 moles of Cl for every mole of CaCl2:
(2moles Cl / 1mole CaCl2) x 4.73 moles CaCl2 = 9.47 moles Cl

Get the mass:
9.47moles Cl x 35.45g/mole = 335.64 g Cl

8 0

3 years ago

Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2

svp [43]

Answer:

The correct option is;

X, W, Y, Z

Explanation:

The parameters given are;

Spring (S), Spring Constant (N/m)

W, 24

X, 35

Y, 22

Z, 15

The equation for elastic potential energy, $E_e$ , is $E_e = 0.5 \times k \times x^2$

The above equation can also be written as $E_e =\dfrac{1}{2} \times k \times x^2$

Where:

k = The spring constant in (N/m)

x = The spring extension

Therefore, since the elastic potential energy, $E_e$ , of the spring is directly proportional to the spring constant, k, we have the springs with higher spring constant will have higher elastic potential energy, $E_e$ , therefore the correct order is as follows;

X > W > Y > Z

9 0

3 years ago