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Gwar [14]
3 years ago
5

across a period, how does the electronegativity of a nonmetal affect the acidity of its binary hydride

Chemistry
1 answer:
goblinko [34]3 years ago
3 0
1) Across the period as one moves from left to right, atomic size decreases.

2) Consider 3rd period elements containing non-metal i.e Si, P, S and Cl.

3) Here, atomic radius of these elements are in following order Si>P>S>Cl.

4) However, electronegative of these elements increases as we move from left to right

5) Thus, the corresponding hydrides have higher electro-negativity difference,as one moves from left to right.

6) Due to this, bond polarity increases from left to right,

7) Increase in bond polarity, results in increasing proton donating capability.

8) Therefore, acidity increases as one moves along the period.  
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The __lithosphere__ combines the two crusts, oceanic and continental, with the coolest part of the __________________. The asthe
zmey [24]

Answer:

The lithosphere And the upper mantle combines the two crusts, oceanic and continental, with the coolest part of the Crust?. The asthenosphere allows the tectonic plates to slide on the putty substance of the mantle and the mesosphere is the Smallest? part of the mantle. The outer core is hot enough to turn the metal into a Liquid The inner core is the hottest but the extreme pressure makes it a Solid.

8 0
2 years ago
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Aluminum has a face-centered cubic unit cell. How many atoms of Al are present in each unit cell
Serjik [45]

Answer:4

Explanation:

As shown in the image attached, a face-centred cubic structure has 8 atoms at the corners and 6 face center atoms.

Each corner atom contributes to eight cell, so per unit cell 1/8 ×8 =1atom

Face center atoms contributes to two unit cells 1/2 × 6=3atoms

Total atoms =3+1=4atoms

Therefore the atoms in Al FCC per unit cell is 4

7 0
3 years ago
Please show all work for full credit.
koban [17]

Answer:

No, it is not sufficient

Please find the workings below

Explanation:

Using E = hf

Where;

E = energy of a photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency

However, λ = v/f

f = v/λ

Where; λ = wavelength of light = 325nm = 325 × 10^-9m

v = speed of light (3 × 10^8 m/s)

Hence, E = hv/λ

E = 6.626 × 10^-34 × 3 × 10^8 ÷ 325 × 10^-9

E = 19.878 × 10^-26 ÷ 325 × 10^-9

E = 19.878/325 × 10^ (-26+9)

E = 0.061 × 10^-17

E = 6.1 × 10^-19J

Next, we work out the energy required to dissociate 1 mole of N=N. Since the bond energy is 418 kJ/mol.

E = 418 × 10³ ÷ 6.022 × 10^23

E = 69.412 × 10^(3-23)

E = 69.412 × 10^-20

E = 6.9412 × 10^-19J

6.9412 × 10^-19J is required to break one mole of N=N bond.

Based on the workings above, the photon, which has an energy of 6.1 × 10^-19J is not sufficient to break a N=N bond that has an energy of 6.9412 × 10^-19J

8 0
2 years ago
PLS help
viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

Sc^{+5}_2O^{-2}_5

For that reason, the answer is d . Sc2O5

Best regards.

3 0
3 years ago
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What’s different about ionic bonding and covalent bonding ? (Help I need the answer ASAP)
Artemon [7]
The two main types of chemical bonds are ionic and covalent bonds. An ionic bond essentially donates an electron to the other atom participating in the bond, while electrons in a covalent bond are shared equally between the atoms. The only pure covalent bonds occur between identical atoms.
3 0
2 years ago
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