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DIA [1.3K]
3 years ago
5

An ideal solenoid of length L, N windings, and radius b (L is much longer than b). A current I is flowing through the wire windi

ngs. If the length of the solenoid becomes twice as long (to 2L), but all other quantities remained the same, the magnetic field inside the solenoid will:
A. would remain the same.
B. would become twice as strong.
C. would become one half as strong.
Physics
1 answer:
umka21 [38]3 years ago
8 0

Answer:

B- would become twice as strong

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Sound energy into electricity?
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The vibrations created by noise can be converted to electrical energy through the principle of magnetic Induction, for example by using transducer.
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3 years ago
What would the weight of an astronaut be on Saturn if his mass is 68 kg and acceleration of gravity on Saturn is 10.44 m/s2? Ple
alex41 [277]

Here's the part you need to know:

       (Weight of anything) =

                 (the thing's mass)
times
                 (acceleration of gravity in the place where the thing is) .

                 Weight = (mass ) x (gravity) .

That's always true everywhere.
You should memorize it.

For the astronaut on Saturn . . .

                   Weight = (mass ) x (gravity) .

                
  Weight =  (68 kg) x (10.44 m/s²)

                        
      =    709.92 newtons .
__________________________________

On Earth, gravity is only  9.8 m/s².
So as long as the astronaut is on Earth, his weight is only

                                   (68 kg) x (9.8 m/s²)

                               =    666.4 newtons .

Notice that his mass is his mass ... it doesn't change
no matter where he goes. 

But his weight changes in different places, because
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4 0
3 years ago
What is the magnitude of the force acting on a spring with a spring constant of 275 N/m that is stretched 14.3 cm?
Travka [436]
15 i thank 
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8 0
3 years ago
A perfect bouncy ball would continue bouncing the same height forever. But in reality, the ball stops bouncing because energy is
galina1969 [7]

Answer:

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6 0
3 years ago
A 75.0 kg person is on a Ferris Wheel that has a radius R = 16 m. The tangential velocity of the Ferris Wheel is 8.25 m/s. Calcu
Dovator [93]

Answer:

The period of rotation is

T=8.025s

Explanation:

The person is undergoing simple harmonic motion on the wheel

Given data

mass of the person =75kg

Radius of wheel r=16m

Velocity =8.25m/s

The oscillating period of simple harmonic motion is given as

T=(2*pi)/2=2*pi √r/g

Assuming that g=9.81m/s

Substituting our data into the expression we have

T=2*3.142 √ 16/9.81

T=6.284*1.277

T=8.025s

3 0
3 years ago
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