1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara31 [8.8K]
3 years ago
15

How does the ability to balance a chemical equation relate to that reaction obeying the Law of Conservation of Matter?

Physics
1 answer:
Aliun [14]3 years ago
8 0
Example: 
<span>CH4 + 2 O2 → CO2 + 2 H2O </span>

<span>In the balanced equation above, 1 mole of CH4 will react with 2 moles of O2 to produce 1 mole of CO2 and 1 mole of H2O. </span>
<span>The mass of 1 mole of CH4 = 12 + (4 * 1) = 16 grams </span>
<span>The mass of 2 moles of O2 = 2 * 32 = 64 grams </span>
<span>Total mass of reactants = 16 + 64 = 80 grams </span>

<span>The mass of 1 mole of CO2 = 12 + (2 * 16) = 44 grams </span>
<span>The mass of 2 moles of H2O = 2 * 18 = 36 grams </span>
<span>Total mass of products = 44 + 36 = 80 grams </span>

<span>Before the reaction, there was 80 grams of matter, and after the reaction there is 80 grams of matter! </span>
<span>Matter is conserved!

</span>
You might be interested in
If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her
Marysya12 [62]

Answer:

 μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

          fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ  = 0

          fr sin θ  - cos θ  (W / 2 + 0,3 W_painter) = 0

          fr = cotan θ  (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

     

X axis

        F1 - fr = 0

        F1 = fr

the friction force has the expression

       fr = μ N

Y Axis

       N - W - W_painter = 0

       N = W + W_painter

       

we substitute

      fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

     μ (W + W_painter) = cotan θ  (W / 2 + 0,3 W_painter)

      μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values ​​they give

      μ = cotan θ  (12/2 + 0.3 55) / (12 + 55)

      μ = cotan θ  (22.5 / 67)

      μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

       cotan 45 = 1 / tan 45 = 1

the result is

    μ = 0.336

5 0
3 years ago
Find the current in the 12 ohm resistor.
disa [49]

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

3 0
3 years ago
What kind of model is shown below?
Rudiy27
D. a foot model



btw this is a joke right cuz there ain’t no picture lol
7 0
3 years ago
A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 610 N horizontal force to set it in motion. After the clo
denpristay [2]

Answer:0.669

Explanation:

Given

mass of clock 93 kg

Initial force required to move it 610 N

After clock sets in motion it requires a force of 514 N to keep moving it with a constant velocity

Initially static friction is acting which is more than kinetic friction

thus 613 force is required to overcome static friction

\mu _smg=610

\mu _s\times 93\times 9.8=610

\mu _s=0.669

5 0
3 years ago
A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and
victus00 [196]

Answer:

a)  t=195.948N.m

b)  \phi=13.6 \textdegree

Explanation:

From the question we are told that:

Density \rho=1.225kg/m^2

Velocity of wind v=14m/s

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient \mu=2.05

a)

Generally the equation for Force is mathematically given by

F=\frac{1}{2}\muA\rhov^2

F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2

F=163.29

Therefore Torque

t=F*r*sin\theta

t=163.29*1.2*sin90

t=195.948N.m

b)

Generally the equation for torque due to weight is mathematically given by

t=d*Mg*sin90

Where

d=sin \phi

Therefore

t=sin \phi*Mg*sin90

195.948=833sin \phi

\phi=sin^{-1}\frac{195.948}{833}

\phi=13.6 \textdegree

5 0
3 years ago
Other questions:
  • 3. A bus accelerates at 25 m/s/s. This allows the bus to speed up from 16 m/s to 172 m/s. How long
    7·1 answer
  • If the mass of a moving object decreases from 100 grams to 25 grams, what happens to its momentum
    10·1 answer
  • How proton ,neutron and electrons are alike
    5·1 answer
  • (29)
    8·1 answer
  • An object has 100J of KE. It has a mass of 10kg. How fast is it travelling
    9·1 answer
  • A lab technician needs to clean medical instruments that have been exposed to bacteria. Which electromagnetic wave would be most
    6·2 answers
  • Can you think of other factors that may affect a carrying capacity
    15·1 answer
  • An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s ). If a particular disk is spun at 235
    9·1 answer
  • A barbel weighing 215N is raised to a height of 2.0 M above the ground. It is then dropped from that height.
    12·1 answer
  • What important component is still scarce for American manufacturers, which had 40 days' worth before the pandemic but only had a
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!