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aev [14]
3 years ago
5

a 12.0L container is filled with a gas to a pressure of 2660 torr at 0°C. At what temp. will the pressure inside the container b

e 3040 torr if volume is held constant?
Physics
1 answer:
Alexxx [7]3 years ago
6 0
\frac{p1}{t1} = \frac{p2}{t2}

Pressure Law: constant volume

Convert all Temperatures to Kelvin

0°C= 273K

\frac{2660}{273} = \frac{3040}{t2} \\ \\ 3040 \times 273 = t2 \times 2660 \\ \\ 829920 \div 2660 = t2 \\ \\ t2 = 312

answer= 312Kelvin
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How can a calculated height be greater than an actual height?
sammy [17]

Answer:

mesuring heigh and weight is important

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2 years ago
At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star
dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

\beta (dB) = 10log_{10}(\frac{I}{I_0})

Where,

I_0 = 1*10^{-12} is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.

I = Sound intensity

Our values are given by,

\beta = 104dB

\#Autos = 7

For each auto the intensity would be,

104 = 10log\frac{I}{1*10^{-12}}

10.4= log_{10} (\frac{I}{10^{-12}})

10^{10.4}*10^{-12}=I

I = 0.02511W/m^2

Therefore the sound intesity for the 7 autos is

I= 7* 0.02511

I = 0.1748W/m^2

The sound level for the 7 cars in dB is

\beta (dB) = 10log_{10}(\frac{0.1748}{1*10^{-12}})

\beta (dB) = 112.42dB

8 0
3 years ago
a mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. if the mass of the object is 0.20kg and the spr
Reil [10]

Answer:

4.06 Hz

Explanation:

For simple harmonic motion, frequency is given by

f=\frac {1}{2\pi}\times \sqrt{\frac {k}{m}} where k is spring constant and m is the mass of the object.

Substituting 0.2 Kg for mass and 130 N/m for k then

f=\frac {1}{2\pi}\times \sqrt{\frac {130}{0.2}}=4.057670803\\f\approx 4.06 Hz

5 0
3 years ago
A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r
sergij07 [2.7K]

Answer:

The workdone is  W = 1.712 *10^{-20 } \  J  

Explanation:

From the question we are told that

    The potential difference is  V  =  107 mV =  107 *10^{-3} \  V

Generally the charge on  Na^{+} is  Q_{Na^{+}} = 1.60 *10^{-19 } \  C

 Generally the workdone is mathematically represented as

         W =  Q_{Na^{+}}V

=>     W = 1.60 *10^{-19 } *  107 *10^{-3}    

=>     W = 1.712 *10^{-20 } \  J    

8 0
3 years ago
Please answer I will give good rating and mark brainlest
lina2011 [118]
The answer is C. You must divide your wavelength and your frequency to get your answer.
8 0
3 years ago
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