It is an example of reflection of wave. C.
The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
where
is the charge density
is the vacuum permittivity
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
Answer:
b. calculate the constant force exerted on the pole vaulter due to the collision
mbgiclbxhkr and you can see the pole and you are not to be a great friend of the day and night sweets is my first day of your life and my friends is my friend
In his celebrated Second Law of Motion, Newton wrote:
Net force = (mass) x (acceleration).
By the process of "plugging in numbers", we can write
1255 N = (41 kg) x (acceleration)
Now, after dividing each side by (41 kg), we have
(1255 N) / (41 kg) = acceleration.
But (1255N)/(41kg) = 30.61 m/s² .
So unless we have carelessly blooped the calculations somewhere,
that 30.61 m/s² is the answer we're looking for.