1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
just olya [345]
3 years ago
6

Describe how ultrasound and infrasound are used in specific industrial applications and provide detailed examples.

Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
In scientific terms, ultrasound is a sound pressure, cyclic in nature, that has a greater frequency than the limit at the top of human hearing capabilities. What this means is that an ultrasonic sound can’t be heard by the human ear because their frequency is too high for our ears to pick up. In healthy young adults, this upper hearing capability is an average of 20 kilohertz. Ultrasound has many applications in several fields. Perhaps the best known application for ultrasound is sonography. This is where medical staff use the high pitched noise to produce a picture of a fetus while in the mother’s womb. Another use however, doesn’t directly concern humans at all. Bats use the high pitched noises to see in the dark and get an accurate reading on their preys internal structure. A popular belief is that an ultrasonic sound has the ability to turn the locking mechanism in a door lock, as demonstrated on some spy movies. On the opposite side of this are infrasonic sounds. These are noises with a frequency less than the lowest level of human hearing capabilities is 20 hertz. It is possible for humans to perceive infrasonic sounds, but only if the air pressure is sufficient. Although the war is the main tool for hearing these low sounds, it is possible for other parts of the body to “feel them”. Infrasound can be used to send signals in the army to special machines that can pick them up. These can be used to transmit vital data. Animals are able to pick up some low infrasonic noises which warn them of natural disasters before they happen, generally earthquakes and tsunamis.


I hope some of this information I gave you can help you. I came up with everything myself to help you.
You might be interested in
a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of
Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               F_t -W = m a

Whera F_t is the trampoline force

Body weight is

                W = mg

We substitute

              F_t - mg = ma

              a =\frac{F_t - m g}{m}

Let's calculate

              a = \frac{375 - 75 \ 9.8 }{75}

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
A pipe open at both ends has a fundamental frequency of 220 Hz when the temperature is 0°C. (a) What is the length of the pipe?
Allushta [10]

Explanation:

It is given that,

Fundamental frequency, f = 220 Hz

(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.

For open pipe, \lambda=2l

l is the length of pipe

Also,

v=f\lambda

l=\dfrac{v}{2f}=\dfrac{331}{2\times 220}=0.75\ m

(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.

v'=331\sqrt{1+\dfrac{T}{273}}

v'=331\sqrt{1+\dfrac{30}{273}}

v' = 348.71 m/s

So, f'=\dfrac{v'}{\lambda}

f'=\dfrac{348.71}{2\times 0.75}

f' = 232.4 Hz

Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N. How far is
Vlad [161]

Mercury is 35.98 million miles from the Sun.

4 0
3 years ago
Read 2 more answers
A radiometer can be used to determine the position of an approaching hot object by measuring the amount of irradiation it detect
forsale [732]

Answer:

The Position of the object L = 0.172 m

Explanation:

The detailed explanation of the question is given in the attach document.

3 0
4 years ago
The sensor in the torso of a crash test dummy records the magnitude znd direction of the net force acting on the dummy.If the du
patriot [66]

Answer : The force will be 4501.9

We can see that, two forces acting on the dummy in two different direction.

We know that, here two forces are given in perpendicular direction with each other.

We know the force is the vector addition law so, we will use the Pythagoras theorem for the resultant of the vectors

Now, the net force is

F_{net} = \sqrt{{F_{1}}^{2}+ {F_{2}}^{2}}

Two forces is given,

F_{1} = 130.0 N

F_{2} = 4500.0 N

Now, the net force is

F_{net} = \sqrt{(130)^{2}+ (4500)^{2}}N

F_{net} = \sqrt{20266900}N

F_{net} = 4501.9 N

Hence, the force will 4501.9 N

8 0
4 years ago
Read 2 more answers
Other questions:
  • If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
    15·1 answer
  • ¿CUAL ES LA CAUSA DE UNA ONDA ESTACIONARIA?
    5·1 answer
  • Recording the location of a star requires a measurement of:
    11·1 answer
  • Which quantity below is a derived quantity?
    8·2 answers
  • What did Rutherford discover about the structure of the atom
    15·1 answer
  • An object has a mass of 24.5 Kilograms and an acceleration of 0 meters per second squared. What would be its first Force in Newt
    12·1 answer
  • PLEASE HELP An object is thrown upward with an initial velocity of 32.1 m/s. What is its velocity in 4.0 s? (use g = 9.81 m/s2).
    7·1 answer
  • Why must indirect evidence be used to study the structure of atoms?
    12·1 answer
  • A flower is red because..?<br><br> Please help! Thank you! I need to get this done ASAP!?!!?
    5·1 answer
  • Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!