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djverab [1.8K]
3 years ago
5

A jet travels 2250 km westward at a speed of 960 km/hr. it then encounters a strong headwind and its speed drops to 805 km/hr fo

r the next 1320 km of its westward trip. what is the average velocity for the trip?
Physics
1 answer:
Kipish [7]3 years ago
4 0
For the first part of the trip:
we have velocity = 960 km/hr and distance = 2250 km
velocity = distance / time
time1 = distance / velocity = 2250 / 960 = 2.34375 hours

For the second part of the trip:
we have velocity = 805 km/hr and distance = 1320 km
velocity = distance / time
time2 = distance / velocity = 1320 / 805 = 1.63975 hours

For the total trip:
we have:
total distance covered = 2250 + 1320 = 3570 km
total time taken = 2.34375 + 1.63975 = 3.9835 hours
average velocity = total distance / total time
average velocity = 3570 / 3.9835 = 896.1968 km/hr
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DedPeter [7]

Answer:

b- a bicycle sitting on the ground

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'Static' means it's not moving.

So, only the answer listed as "a bicycle sitting on the ground" corresponds to that condition.

All others possible answers describe something that is moving (an apple falling, a motorcycle accelerating, a car moving at a constant speed).  Even if they are going at a constant speed, they are moving, so not static.

6 0
4 years ago
Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

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Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
4 years ago
PLEASE HELP ME PLEASE
Afina-wow [57]

Answer:

For A

Displacement= 1/2*3*6= 9m

For B

Displacement= 1/2*4*4= 8m

5 0
3 years ago
ASAP do all will give 25 per person pls will mark brainiest
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Answer:

1) true

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3) false

4) true

5) true

6) true

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8) false

9) true

10) false

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4 0
3 years ago
How much work is done if you push a box 200 meters with a force of 35 newtons answer?
VashaNatasha [74]
Work = force × distance
= 35 N × 200 m
= 7000 J
4 0
3 years ago
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