Three-dimensional ____ programs allow designers to rotate designs of 3-d objects to view them from any angle.

The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .

vlabodo [156]

Answer: $90\°$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when the photons are scattered is given by the following equation:

$\Delta \lambda=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}c}$ , being $h$ the Planck constant, $m_{e}$ the mass of the electron and $c$ the speed of light in vacuum.

$\theta)$ the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through $180\°$ :

$\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))$ (2)

$\Delta \lambda_{max}=\lambda_{c}(1-(-1))$

$\Delta \lambda_{max}=2\lambda_{c}$ (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)$ (4)

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)$ (5)

If we want $\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}$ , $1-cos\theta$ must be equal to 1:

$1-cos\theta=1$ (6)

Finding $\theta$ :

$1-1=cos\theta$

$0=cos\theta$

$\theta=cos^{-1} (0)$

Finally:

$\theta=90\°$ This is the scattering angle that will produce $\frac{1}{4}\Delta \lambda_{max}$

7 0

3 years ago

How many protons are in Calcium? (* Hint: The Atomic number of Calcium is 20).

ryzh [129]

Answer:

The answer to your question is: 20

Explanation:

Atomic number is the number of proton and atom has. Each element has a specific number of protons, if the number of protons change, then this is a new element.

Mass number is the number of protons and neutrons and atom has.

Mass number = protons + neutrons

Data

Number of protons = ?

Atomic number = 20

Then,

atomic number = number of protons = 20

3 0

2 years ago

A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).

PIT_PIT [208]

The kayaker has velocity vector

v = (2.50 m/s) (cos(45º) i + sin(45º) j )

v ≈ (1.77 m/s) (i + j )

and the current has velocity vector

w = (1.25 m/s) (cos(315º) i + sin(315º) j )

w ≈ (0.884 m/s) (i - j )

The kayaker's total velocity is the sum of these:

v + w ≈ (2.65 m/s) i + (0.884 m/s) j

That is, the kayaker has a velocity of about ||v + w|| ≈ 2.80 m/s in a direction θ such that

tan(θ) = (0.884 m/s) / (2.65 m/s) → θ ≈ 18.4º

or about 18.4º north of east.

5 0

3 years ago

A piece of clay sits 0.10 m from the center of a potter’s wheel. If the potter spins the wheel at an angular speed of 15.5 rad/s

finlep [7]

Answer:

$a=24.025\ m/s^2$

Explanation:

Given that

Distance from the center ,r= 0.1 m

The angular speed ,ω = 15.5 rad/s

We know that centripetal acceleration is given as

a=ω² r

a=Acceleration

r=Radius

ω=angular speed

a=ω² r

Now by putting the values in the above equation we get

$a=15.5^2\times 0.1\ m/s^2$

$a=24.025\ m/s^2$

Therefore the acceleration of the clay will be $a=24.025\ m/s^2$ .

4 0

3 years ago

Help me its emergency I need a correct answer please if you don't know then please dont guess

maxonik [38]

Answer:

True.

Explanation:

Total internal reflection is bound to occur when light travels from dense medium to less dense.

From the table given in the question above, we obtained:

Refractive Index of Crown glass = 1.52

Refractive Index of Asphalt = 1.635

From the above, Crown glass has a lower refractive index when compared to Asphalt. This means that Crown glass is less dense than Asphalt.

Therefore, total internal reflection will not occur when light travels from Crown glass to Asphalt because Crown glass is less dense than Asphalt.

7 0

2 years ago