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Natasha2012 [34]

3 years ago

13

Hey everyone!

1 answer:

Soloha48 [4]3 years ago

6 0

8. In soft magnetic materials such as iron, what happens when an external magnetic field is removed? a. The domain alignment persists. b. The orientation of domains fluctuates. c. The material becomes a hard magnetic material. d. The orientation of domains changes, and the material returns to an unmagnetized state. 9. According to Lenz’s law, if the applied magnetic field changes, a. the induced field attempts to keep the total field strength constant. b. the induced field attempts to increase the total field strength. c. the induced field attempts to decrease the total field strength. d. the induced field attempts to oscillate about an equilibrium value. 10. The direction of the force on a current-carrying wire in an external magnetic field is a. perpendicular to the current only. b. perpendicular to the magnetic field only. c. perpendicular to the current and to the magnetic field. d. parallel to the current and to the magnetic field

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Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3

Y_Kistochka [10]

Answer:

Ro = 8.65 [g/cm³]

Explanation:

We must remember that density is defined as the ratio of mass to volume.

$Ro=m/V$

where:

m = mass = 0.450 [kg] = 450 [g]

V = volumen = 52 [cm³]

Ro = density [g/cm³]

Now replacing:

$Ro = 450/52\\Ro = 8.65 [g/cm^{3} ]$

8 0

2 years ago

The truck in which

sertanlavr [38]

Answer:

m = 4

Explanation:

We have,

You apply a force of 600 N to the branch which acts as a lever. It means it is input force, IF = 600 N

The rear of the truck weighs 2,400 N. It means it is output force, OF = 2400 N

The ratio of output force to the input force is equal to the mechanical advantage of the lever arm. It is given by :

$m=\dfrac{2400}{600}\\\\m=4$

So, the mechanical gain of the lever arm is 4.

8 0

2 years ago

ludmilkaskok [199]

Answer:

1) ironing a shirt 2) writing on surfaces 3) working of an eraser

5 0

2 years ago

An electromagnetic wave of intensity 150 W/m2 is incident normally on a rectangular black card with sides of 25 cm and 30 cm tha

LenKa [72]

Answer:

3.75 × 10⁻⁸ N

Explanation:

Given:

Intensity of the electromagnetic wave, I = 150 W/m²

Sides of the board = 25 cm (= 0.25 m) and 30 cm (= 0.30 m)

therefore,

the area of the rectangular box, A = 0.25 × 0.30 = 0.075 m²

Now,

force exerted on the card by the radiation, F = $\frac{IA}{C}$

here,

C is the speed of the light = 3 × 10⁸ m/s

on substituting the respective values, we get

F = $\frac{150\times0.075}{3\times10^8}$

or

F = 3.75 × 10⁻⁸ N

5 0

2 years ago

a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien

Law Incorporation [45]

Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

Explanation:

Using the definition of the centripetal force we have:

$\Sigma F=ma_{c}=m\frac{v^{2}}{R}$

Where:

m is the mass of the car
v is the speed
R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

$F_{f}=m\frac{v^{2}}{R}$

$F_{f}=2100\frac{18^{2}}{83}$

$F_{f}=8197.60 \: N$

<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

7 0

3 years ago