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Travka [436]
3 years ago
7

Calculate the amount of potential energy a 200 kg car has on top of a 15 m hill

Chemistry
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

29430J

Explanation:

g=9.81m/s^2

Pe=mgh=200*9.81*15=29430J (joule)

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Which is a practical application of boiling-point elevation?
pishuonlain [190]
Boiling-point is the point of a pure liquid matter starts to evaporate and change into gaseous phase. It is where the set of conditions such as the pressure and temperature enough to do so. Boiling-point elevation, on the other hand, is the phenomenon of which the boiling point of a pure liquid matter is elevated because of the dissolved substances. A great example would be the boiling point of a distilled water (pure water) which is lesser than the boiling point of a sea water because of the dissolved salts. A pure water boils at 100°C at atmospheric pressure while a salt water boils at higher temperature than 100°C at the same pressure. Thus, the answer is D.
7 0
3 years ago
A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC
inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0
3 years ago
What existed during the mesozoic era
Ilia_Sergeevich [38]
Mezoic era began 252m years ago and ended 6.6m years ago.
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I hope this helped. :)
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3 years ago
Describe the cell structure of a typical plant cell
aleksley [76]

Answer:

Wrong subject my friend.

4 0
3 years ago
If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra
docker41 [41]

Answer :

(a) The moles of CrO_3 is, 1.5 moles.

(b) The number of oxygen atoms are, 27.099\times 10^{23}

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of CrO_3 = 150 g

Molar mass of CrO_3 = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of CrO_3.

\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles

The moles of CrO_3 is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In CrO_3, there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of CrO_3 contains 3\times 6.022\times 10^{23} number of oxygen atoms.

So, 1.5 mole of CrO_3 contains 1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23} number of oxygen atoms.

The number of oxygen atoms are, 27.099\times 10^{23}

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of CrO_3 contains 3 moles of oxygen

So, 1.5 mole of CrO_3 contains 1.5\times 3=4.5 moles of oxygen

\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}

\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g

The mass of oxygen is, 72 grams.

3 0
3 years ago
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