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Gekata [30.6K]
3 years ago
5

A particle-level diagram of a metallic element is shown above. Typically, metals are both malleable and ductile. The best explan

ation for these properties is that the electrons involved in bonding among metal atoms are:.
Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

The properties of malleability and ductility can all be explained on the basis of metallic bonding.

<h3>What is malleability?</h3>

The term malleability refers to the ability of a metal to be hammered into sheets. It is a very important property of metals that helps in metal work. The images are not shown here hence the question is incomplete.

Ductility refers to the ability of metals to be drawn into sheets. This is the reason why metals can be used to make wires. All these properties are explained on the basis of metallic bonding.

Learn more about metallic bonding: brainly.com/question/10714037

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In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.
mihalych1998 [28]

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

8 0
4 years ago
An ate or ite at the end of a compound name usually indicates that the compound contains___________.
Ymorist [56]

Answer:

D

Explanation:

According to IUPAC nomenclature, a negative polyatomic ion has its name ending in 'ate' or 'ite'

As in carbonate (CO3^2-)

Arsenite (AsO3-)

3 0
3 years ago
Read 2 more answers
A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s
Alla [95]

<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaBr:</u>

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol

The chemical equation for the reaction of 1-butanol and NaBr is:

\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = \frac{1}{1}\times 0.108=0.108 moles of 1-bromobutane

  • Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g

  • To calculate the percentage yield of 1-bromobutane, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0
3 years ago
1) A toy car with a mass of 2.35 kg is pushed with a force of 21.6 N. What is the acceleration of the car?
Nataly_w [17]

Answer:

The acceleration of the car is 9,19 m/s2

Explanation:

We use the formula: F=m x a---> a=F/m

a=21,6N/ 2,35kg       1N is 1kgxm/s2

a=21,6 kg x m/s2 x 2,35 kg

a=9,191489362  m/s2

6 0
3 years ago
Sometimes a cloud may form at or near the ground when the ground cools at night. This cloud is known as...
melomori [17]

Answer:

im belive the answers fog

8 0
3 years ago
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