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3 years ago

Which equation obeys the law of conservation of mass?

Chemistry

2 answers:

Gala2k [10]3 years ago

8 0

Explanation:

According to law of conservation of mass, total mass of reactants will be equal to the total mass of products.

For example, $HCl + NaOH \rightarrow NaCl + H_{2}O$

Therefore, mass of reactant molecules will be as follows.

Mass of HCl is 36.46v g/mol

Mass of NaOH is 39.99 g/mol

Total mass of reactants is (36.46 + 39.99) g/mol = 76.45 g/mol

Mass of product molecules will be as follows.

Mass of NaCl is 58.44 g/mol

Mass of $H_{2}O$ is 18.01 g/mol

Total mass of products is (58.44 + 18.01) g/mol = 76.45 g/mol

Thus, we can conclude that any equation which represents total mass of reactants equal to the total mass of products is actually obeying the law of conservation of mass.

elena55 [62]3 years ago

3 0

4Fe + 3O2 → 2Fe2O3, hope this helps man!

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3 years ago

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Answer:

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Explanation:

¡Hola!

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3 years ago

If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?

Pie

Answer:

$m = \frac{E}{c^2}$

$c = \sqrt{\frac{E}{m} }$

$E = 12.8 J$

Explanation:

Part 1: Solving for m

We are given that:

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

$m = \frac{E}{c^2}$

Part 2: Solving for c

We are given that:

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

$c^2 = \frac{E}{m}\\ \\ c=\sqrt{\frac{E}{m}}$

Part 3: Solving for E

We are given that:

m = 80 and c = 0.4

To get the value of E, we will simply substitute in the given equation:

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

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