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sweet-ann [11.9K]
3 years ago
5

Which equation obeys the law of conservation of mass?

Chemistry
2 answers:
Gala2k [10]3 years ago
8 0

Explanation:

According to law of conservation of mass, total mass of reactants will be equal to the total mass of products.

For example, HCl + NaOH \rightarrow NaCl + H_{2}O

Therefore, mass of reactant molecules will be as follows.

Mass of HCl is 36.46v g/mol

Mass of NaOH is 39.99 g/mol

Total mass of reactants is (36.46 + 39.99) g/mol = 76.45 g/mol

Mass of product molecules will be as follows.

Mass of NaCl is 58.44 g/mol

Mass of H_{2}O is 18.01 g/mol

Total mass of products is (58.44 + 18.01) g/mol = 76.45 g/mol

Thus, we can conclude that any equation which represents total mass of reactants equal to the total mass of products is actually obeying the law of conservation of mass.

elena55 [62]3 years ago
3 0
4Fe + 3O2 → 2Fe2O3, hope this helps man!
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based on the cause and effect relationship between the magnets, which phenomenon is the teacher modeling for her students.
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2 years ago
Baking soda NaHCO3, is made from soda ash, a common name for sodium carbonate. The soda ash is obtained in two ways. It can be m
Vaselesa [24]

Answer:

Explanation:

From the given information:

mass of silver chloride AgCl = 11.89 g

molar mass of AgCl = 143.37 g/mol

We know that:

number of moles = mass/molar mass

∴

number of moles of AgCl = 11.89 g/ 143.37 g/mol

number of moles of AgCl = 0.0829 mol

The chemical equation for the mineral called trona is:

\mathsf{Na_2CO_3.NaHCO_3.2H_2O}

when being reacted with hydrochloric acid, we have:

\mathsf{Na_2CO_3.NaHCO_3.2H_2O + 3HCl \to 3NaCl + 2CO_2 +4H_2O}

One mole of NaCl formed from one mole of trona sample = 0.0829 moles of AgCl

i.e. 0.0829 moles of NaCl can be formed from AgCl

mass of trona sample = number of moles × molar mass

mass of trona sample = 0.0829 × 226

mass of trona sample = 18.735 g

The mass in the percentage of NaHCO₃ = mass of NaHCO₃/ mass of trona

The mass in the percentage of NaHCO₃ = 6.93/18.735

The mass in the percentage of NaHCO₃ = 0.36989

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8 0
3 years ago
If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum
monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

                    3.55 mg ----------------- 1 oz

                      x    mg  -----------------12 oz (in a can)

x = 42.6 mg of caffeine in a can

Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can

Finally

            0.0426 g of caffeine ------------------  1 can

            10           g of caffeine -----------------    x

x = 10 x 1/0.0436 = 234.7 cans

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