On top: (-2)³ = -2 × -2 × -2 = -8
(x²)³ = x^6 (the exponents multiply)
and of course, (y)³ = y³
On the bottom: (xy²z)² = x² y^4 z²
(-yz)² = y²z²
Multiplying these together, the exponents add and we get x² y^6 z^4.
So, your reasoning is correct for what you have so far.
Your next step would be cancelling shared factors from the top and bottom.
Just like with regular fractions, if the numerator and denominator are divisible by the same number, you can divide them by it to simplify. (ex: 4/6 = 2/3)
Well, x^6 and x^2 are both divisible by x^2, right?
We can also cancel the y^3.
It might help to visualise the factors like this:
Once you've cancelled out x² and y³ from each, you're left with
Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
Quadrilateral DEFG is congruent with Quadrilateral SPQR
Solve for x
we know that
If two figures are congruent, then its corresponding sides and its corresponding angles are congruent
we have that
GF and RQ are corresponding sides
so
RQ=GF
substitute the given values
solve for x
adds 4 both sides
divide by 2 both sides
Answer:
9/25
Step-by-step explanation:
find a number that both the top and bottom are divisible by,
23 is the greatest common division we can make such that the top and bottom remain whole numbers
so,
÷23
=(207/23)÷(575/23)
=
Answer:
(7, 46)
Step-by-step explanation:
The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...
x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not
x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set
x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set
Of the choices offered, only (7, 46) is in the solution set.
There were 3 pieces of pie and two kids wanted them. You gave each give one full piece of pie and then cut the last piece in half. After this, each kid had 1 1/2 pieces of pie.
