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yulyashka [42]
3 years ago
11

How do you make a Lewis Electron Dot Structure?

Physics
1 answer:
Maru [420]3 years ago
6 0
<span>First, you can gather the number of valence electrons. Then find the number of electrons. Do that to make the atoms. Molecules make up atoms. After you need to find how many bonds are in the molecule, which molecules are made up of atoms. Then lastly you find the central atom. </span>
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Temperature is
Colt1911 [192]

Answer:

The 1st and the 3rd answer

7 0
3 years ago
What is value of g in space
makvit [3.9K]
The acceleration of gravity toward any object depends on its mass
and your distance from its center. 

In space, the size AND DIRECTION of 'g' depends on the masses
around you and your distance from the center of each one. 

If there's one object ... like a planet or a star ... that's bigger than
any others and closer to you than any others, then you can ignore
the others and just calculate the acceleration of 'g' toward that one
object that drowns out the others.

Example:

If you're in space only a few hundred miles from the surface of the
Earth, like maybe on board the International Space Station, then the
'g' on you is practically all due to the Earth and the sun, and you can
ignore the effects of gravity pulling you toward Jupiter, toward the Moon,
and toward the space station itself.
4 0
4 years ago
A projectile is fired from the ground (you can assume the initial height is the same as the ground) in a field so there are no o
I am Lyosha [343]

Answer:

(A)  111.77m

(B) 9.07m

(C)55.88m/s

(D)20.54m/s

Explanation:

step 1 " we have to calculate the time it took the projectile to get to its maximum height

(a)  t = usinθ/g

= 49sin 33/9.81

49×0.5446/9.81

=2.72s

the horizontal distance =  ucosθ×t  , because the projectile horizontal motion is unaffected by the force of graavity

= 49cos33 ×2.72

=111.77m

(B) with the same projectile fired the same way , the horizontal distance = 55.8m

55.8 = ucosθ×t

55.8 = 49cos33 ×t

t = 55.8/49cos33

t= 1.36s

height of the projectile = 1/2 ×g×t²

=1/2 ×9.81×1.36²

= 9.07m

(c) Velocity of the projectile when it hits the wall

V₀ = ucosθ×t

49cos 33 × 1.36

=55.88 m/s

(D) speed = distance / time

distance /2×t   ; total time of flight

= 55.88/ 2.72

=20.54m/s

4 0
3 years ago
Three blocks are arranged in a stack on a frictionless horizontal surface. The bottom block has a mass of 37.0 kg. A block of ma
Alex777 [14]

Answer:

N₂ = 503.8 N

Explanation:

given,

mass of bottom block = 37 Kg

mass of middle block = 18 Kg

mass of the top block = 16 Kg

force acting on the top block = 170 N

force on the block at top

N₁ be the normal force from block at middle

now,

N₁ = 170 + m g

N₁ = 170 + 16 x 9.8

now, force on block at middle

N₂ be the normal force exerted by the bottom block

N₂ = N₁ + m₂ g

N₂ = 326.8 + 18 x 9.8

N₂ = 503.8 N

hence, normal force by bottom block is equal to N₂ = 503.8 N

7 0
4 years ago
How can one tell if an object can absorb light or not? How about transmit?<br> Thank you!
kondaur [170]

<u>Absorb:</u>
Shine a light with known intensity into the object. 
Measure the intensity of the light that comes out.
Any light that goes in but doesn't come out the other side
   was absorbed by the object.
(Note:  You also need to be aware of any light that bounces back from
the first side without entering the object.  That light is <em><u>reflected</u></em> from it,
and can't be expected to show up at the other side.)

<u>Transmit:</u>
Any light that goes in and DOES come out the other side
   was transmitted by the object.


4 0
3 years ago
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