All categories

3 years ago

How do you make a Lewis Electron Dot Structure?

1 answer:

6 0

<span>First, you can gather the number of valence electrons. Then find the number of electrons. Do that to make the atoms. Molecules make up atoms. After you need to find how many bonds are in the molecule, which molecules are made up of atoms. Then lastly you find the central atom. </span>

You might be interested in

What type of energy is the sum of an object’s potential and kinetic energy?

nikklg [1K]

Answer: its mechanical energy

Explanation:

8 0

4 years ago

at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g

labwork [276]

<h2>She will find the ball at a horizontal distance of 86.4 m from landed location</h2>

Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 2 m/s

Acceleration, a = 9.81 m/s²

Displacement, s = 100 m

Substituting

s = ut + 0.5 at²

100 = 2 x t + 0.5 x 9.81 xt²

4.905t² + 2t - 100 = 0

t = 4.32 s or t = -4.72 s

After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 20 m/s

Acceleration, a = 0 m/s²

Time, t = 4.32 s

Substituting

s = ut + 0.5 at²

s = 20 x 4.32 + 0.5 x 0 x 4.32²

s = 86.4 m

She will find the ball at a horizontal distance of 86.4 m from landed location

5 0

4 years ago

The center of mass of a cow and the center of mass of a tractor are 208 meters apart. The magnitude of the gravitational force o

hjlf

Answer:

$4.5\times 10^{-10}\ N$

Explanation:

The gravitational force between two masses is inversely proportional to the square of the distance between them such that,

$\dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}$ .....(1)

We have,

r₁ = 208 m, $F_1=1.8\times 10^{-9}\ N$ , r₂ = 416 m, F₂ = ?

Put all the values in relation (1) such that,

$F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1.8\times 10^{-9}\times 208^2}{416^2}\\\\F_2=4.5\times 10^{-10}\ N$

So, the required force is $4.5\times 10^{-10}\ N$ . Hence, the correct option is (d).

7 0

3 years ago

You have to connect each one to right answers 1.concave lens, magnifier, focal length, wavelength, infrared radiation,real pictu

nignag [31]

$\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\frac{a}{b}$ $\sf\red{hope\:it\:helps\:you}$ $\huge\pink{\mid{\fbox{\tt{your\:QUESTION}}\mid}}$ $\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}$

-,-

$\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$ $\bold{\huge{\fbox{\color{maroon}{ANSWER}}}}$

-,-

❥⸻➤ ${\pink{\tt{Mixedfarming}}}$

3 0

3 years ago

A child on a tricycle is moving at a speed of 1.40 m/s at the start of a 2.25 m high and 12.4 m long incline. The total mass is

goblinko [34]

Answer:

The work done by the child as the tricycle travels down the incline is 416.96 J

Explanation:

Given;

initial velocity of the child, $v_i$ = 1.4 m/s

final velocity of the child, $v_f$ = 6.5 m/s

initial height of the inclined plane, h = 2.25 m

length of the inclined plane, L = 12.4 m

total mass, m = 48 kg

frictional force, $f_k$ = 41 N

The work done by the child is calculated as;

$\Delta E_{mech} = W - f_{k} \Delta L\\\\W = \Delta E_{mech} + f_{k} \Delta L\\\\W = (K.E_f - K.E_i) + (P.E_f - P.E_i) + f_{k} \Delta L\\\\W = \frac{1}{2} m(v_f^2 - v_i^2) + mg(h_f - h_i) + f_{k} \Delta L\\\\W = \frac{1}{2} \times 48(6.5^2 - 1.4^2) + 48\times 9.8(0-2.25) + (41\times 12.4)\\\\W = 966.96 \ - \ 1058.4 \ + \ 508.4\\\\W = 416.96 \ J$

Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J

5 0

3 years ago