All categories

3 years ago

If the x and y vector components of Vector A are 11 and 7,

Physics

1 answer:

riadik2000 [5.3K]3 years ago

5 0

Answer:

R=13.04

Explanation:

Using pythagoras theorem

Assuming the vector A is the resultant force R

R^2=11^2+7^2

R^2=121+49

R^2=170

R=13.038

R=13.04

You might be interested in

Can someone help me plz

yKpoI14uk [10]

The height increases (c)

5 0

2 years ago

What measurements or observations tells you that a car is accelerating

lutik1710 [3]

You need to observe the car at two different times.

-- The first time:
You write down the car's speed, and the direction it's pointing.

-- The second time:
You write down the car's speed and the direction it's pointing, again.

You take the data back to your lab to analyze it.

-- You compare the first and second speed. If they're different,
then the car had acceleration during the time between the two
observations.

-- You compare the first and second direction. If those are different,
even if the speeds are the same, then the car had acceleration during
the time between the two observations.

(Remember, "acceleration" doesn't mean "speeding up".
It means any change in speed or direction of motion.)

8 0

3 years ago

Read 2 more answers

Una rueda gira con una frecuencia de 530 rpm. Determina la velocidad angular, el periodo y la frecuencia.

Vlad1618 [11]

Answer:

donde esta la bibliotekaaa

Explanation:

dfghj

6 0

2 years ago

A man has a mass of 85kg, what is his weight

Ostrovityanka [42]

The answer is he weighs 187.39 LBS/Pounds

5 0

3 years ago

Read 2 more answers

Driving along a boring stretch of interstate in Illinois, you start experimenting using the average speed equation you learned i

astra-53 [7]

The average speed would be 33.29m/s.
The average speed equation is:

$Average speed = \frac{total distance}{total time}$

First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled.

Scenario 1:
Speed = 29m/s
Time = 120s
Distance = ?

Distance = (29m/s)(120s)
= 3,480m

Scenario 2
Speed = 35m/s
Time = 300s
Distance = ?

Distance = (35m/s)(300s)
= 10,500m

Now that you have the distance of both, you can solve for your average speed.

$Average speed = \frac{total distance}{total time}$
$= \frac{3,480m+10,500m}{120s+300s}$
$= \frac{13,980m}{420s}$
$= 33.29m/s$

5 0

3 years ago