Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
- 
, where
and 
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴ 
and 
∴ 
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
Adyacente=hipotemusa*coseno del angulo
A=6*cos(65)
A=2.54m
Una pregunta, ¿estudias en educazion.net?
Answer:
77
Step-by-step explanation:
Firstly, we need to calculate the total score of the junior students and the total score of the senior students.
The total score of the junior students is 35 * 80 = 2,800
The total score of the senior students is 15 * 70 = 1050
The total score is thus 2,800 + 1,050 = 3,850
The average score of the 50 students is thus 3,850/50 which equals 77
Answer:
=2a
Step-by-step explanation:
a-2/5a and a+2/5a cancel each other out and your left with a+a aka 2a
