Answer:
The value of n in the hydrate formula is 5 ,
.
Explanation:
![CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O](https://tex.z-dn.net/?f=CuSO_4.nH_2O%5Crightarrow%20CuSO_4%2BnH_2O)
Mass of hydrate of copper sulfate = 14.220 g
Moles of hydrate of copper sulfate =![\frac{14.220 g}{(159.5+n\times 18) g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B14.220%20g%7D%7B%28159.5%2Bn%5Ctimes%2018%29%20g%2Fmol%7D)
Mass of copper sulfate after heating = 8.9935 g
Moles of copper sulfate = ![\frac{8.9935 g}{159.5 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B8.9935%20g%7D%7B159.5%20g%2Fmol%7D)
![\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B14.220%20g%7D%7B%28159.5%2Bn%5Ctimes%2018%29%20g%2Fmol%7D%3D%5Cfrac%7B8.9935%20g%7D%7B159.5%20g%2Fmol%7D)
Solving for n, we get:
n = 5
The value of n in the hydrate formula is 5 ,
.
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:
10 mol NH3 ( 6.022 x 10^23 molecules / 1 mol ) = 6.022x10^24 molecules NH3
Answer:
Most substituted alkene is produced as a major product
Explanation:
- Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
- Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
- Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
- Reaction mechanism has been shown below.