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UkoKoshka [18]
3 years ago
10

The particles of a substance lose energy and change from

Chemistry
1 answer:
svp [43]3 years ago
5 0

Answer:

A Liquid

Explanation:

structure with large distance (gas) than goes to a loosely ordered state (liquid)

I hope this helps

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B) Name three substances which can undergo sublimation and deposition respectively​
SpyIntel [72]

solid carbon dioxide, iodine, arsenic, and naphthalene

Explanation:

Examples of substances that undergo sublimation

Examples of solids that sublime are dry ice (solid carbon dioxide), iodine, arsenic, and naphthalene (the stuff mothballs are made of).

3 0
3 years ago
Write a sentence that descrices how to determine the number of moles of a compound in known mass of a
sattari [20]

Explanation:

<u>Moles is denoted by given mass divided by the molecular mass ,  </u>

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

For example ,

For  a compound X ,

The given mass i.e. w = 20 g

and the molecular mass ,i.e. , m = 10 g / mol

Then the moles can easily be calculated by using the above formula ,

n = w / m

n = 20 g / 10 g/mol = 2 mol

Hence , answer = 2 mol.

6 0
3 years ago
In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina
aliya0001 [1]
Answer is: <span>the molarity of HCl is </span>0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M. 
8 0
3 years ago
Please answer truthfully:))​
makvit [3.9K]

Answer:

Fast, Direction, Time

Explanation:

4 0
3 years ago
Since density depends on the mass and volume of an object, we need both of these values combined in the correct way to solve for
alukav5142 [94]

Answer:

  7.86 g/cm³

Explanation:

  11.0 kg = 11,000 g

The density in g/cm³ is ...

  (11,000 g)/(1,400 cm³) = 7.86 g/cm³

7 0
3 years ago
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