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2 years ago

Please answer number 76,77 and 78.

Chemistry

1 answer:

mote1985 [20]2 years ago

3 0

76. The level of muddy water will decrease slightly if the model is left in a sunny location for several days because of Evaporation. The sun will vaporize the water found in the mud, turning it into it's gaseous state, which will then cause it to rise up and get stuck on the plastic wrap.

77. Precipitation

78.The reason that the sediment in the muddy water will remain the same is because the Mud will never evaporate like the water will, and therefore it will remain at the bottom of the container.

Hope that helps!

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3 years ago

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2 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

$3NO_{2} +H_{2}O -->2HNO_{3} +NO$

Then we calculate the number of moles of nitric acid produced

n(HNO3) = $\frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol$

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

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2 years ago

7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.

goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

6 0

3 years ago

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