Answer:
B. the force of friction of the road on the tires
Explanation:
Unless the car engine is like jet engine, the main force that accelerates the car forward is the force of friction of the road on the tires, which is ultimately driven by the force of engine on the tires shaft. As the engine, and the shaft are part of the system, their interaction is internal. According to Newton laws of motion, the acceleration needs external force, in this case it's the friction of the road on the tires.
Answer:
Fc=5253
N
Explanation:
Answer:
Fc=5253
N
Explanation:
sequel to the question given, this question would have taken precedence:
"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."
so we derive centripetal acceleration first
ac (centripetal acceleration) = v^2/r
make r the subject of the equation
r= v^2/ac
ac is 6.23*g which is 9.81
v is 101m/s
substituing the parameters into the equation, to get the radius
(101^2)/(6.23*9.81) = 167m
Now for part
( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.
he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.
Fc (Centripetal Force) = m*v^2/r
So (86kg* 101^2)/(167) =
Fc=5253
N
The answer for this question is b because it says how far it goes before he begins to take brake
Answer:
<u>400</u> J work is done BY the engine.
The internal energy of the gas is <u>620</u> J
Explanation:
The given information are;
The heat added to the cylinder = 620 J
The force applied by the piston of the engine = 8.0 kN = 8,000 N
The distance over which the force moves (the piston) = 5.0 cm = 0.05 m
The work done (by the engine) = Force × Distance = 8,000 N × 0.05 m = 400 J
The internal energy is the sum of the kinetic and potential energy of the system
Therefore, given that the internal energy, U, is the sum total of the energy in the system
∴ U = The heat supplied to the system = 620 J
Which gives;
<u>400</u> J work is done BY the engine.
The internal energy of the gas is <u>620</u> J.
Neither technician is correct.
Please don't touch my car.
