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3 years ago

What is the answer for number 2 and 4 thank you

Mathematics

1 answer:

DaniilM [7]3 years ago

5 0

Welcome to the era of LeBron. If you thought he was doing the game a disservice by being a sore loser and egomaniac, you haven’t seen anything yet. It wasn’t enough that he decided to become a pariah, he and his group of cronies have decided they want to ruin the NBA.

How? By systematically turning every superstar in the NBA into LeBron James. They are trying to turn them into spoiled, delusional, lying, quitting cowards.

Two of the biggest stories this offseason have been the drama in Denver and New Orleans. Both players, for whatever reasons, have decided that they no longer want to be the cornerstone of a franchise. Before the summer of Lebron, neither had really been asking to get out of their situations. So what is the common thread here? Well, both are represented by agent Leon Rose. Who else is represented by Rose? Why Mr. James, of course.

You might be interested in

What is 2x squared times by 4

mina [271]

Since you can only multiply the 2 and 4 together, you get 8x^2.

8 0

3 years ago

Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c

nadya68 [22]

Answer:

$A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]$ message SHOW_ME_THE_MONEY_

Step-by-step explanation:

The matrix

$A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\$

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message Decoded message message in letters by association

11 52 19 8 S H

-8 -9 15 23 O W

-13 -39 0 13 _ M

5 20 5 0 E _

12 56 20 8 T H

5 20 5 0 E _

-2 7 13 15 M O

9 41 14 5 N E

25 100 25 0 Y _

Then the message decoded is SHOW_ME_THE_MONEY_

3 0

2 years ago

Write each fraction or mixed number as a decimal. 19/25 311/500 5/8 145/8

DanielleElmas [232]

Answer:

19/25 = 0.76

311/500 = 0.622

5/8 = 0.625

145/8 = 18.12500

Step-by-step explanation:

Divide the first number by the second like 145 divided by 18.

5 0

3 years ago

Read 2 more answers

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago

Multiply (2n + 2)(2n – 2) A. 4n 2 – 4 B. 4n 2 – 4n – 4 C. 4n 2 + 2n – 4 D. 4n 2 + 4n – 4

sattari [20]

This system can be a bit tricky unless you write it out:
(2n + 2)(2n - 2) ~ First you have to take one variable and multiply it to each of the other two variables, like:
2n * 2n ~ And:
2n * -2 ~ This gives you:
4n^2 - 4n
Now we do this with the other:
2 * 2n
2 * -2
4n - 4
Now we combine them both while adding like terms:
4n^2 - 4
Therefore your answer is: A. 4n^2 - 4
(This is due to how when having the positive 4n subtracted by the negative it cancels it out. Leaving us with the remaining two terms left.)

I hope this helps, have a great rest of your day! ^ ^
~Ghostgate

7 0

2 years ago