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denis-greek [22]
3 years ago
15

Which part of a bird's body is least likely to be preserved as a fossil? A. skeleton B. feathers C. skin D. internal organs E. b

eak
Chemistry
2 answers:
Neporo4naja [7]3 years ago
7 0
D. Internal organs, Organs will break down and be eaten by bugs and such postmortem
White raven [17]3 years ago
6 0
In general, the skeleton is usually what becomes preserved in fossil. This is because over time, soft tissues and organs will degrade and decompose before the necessary time passes for fossilization. Bones are much more rigid and are able to overcome the process of fossilization. Based on this information, we can eliminate the skeleton and probably the feathers. We can eliminate feathers because we know and have evidence that feathers are capable of being fossilized. I would also say that we could eliminate the beak for this question. That's because birds' beaks are made of a protein called beta keratin, which is quite hard and durable. This leaves you with the decision of either the skin or internal organs. Which one do you think would degrade first? Think about the predators that may come by and eat parts of the bird after it dies. 
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When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

7 0
3 years ago
An atom in the ground state contains 8 valence electrons this atom is classified as a
Alekssandra [29.7K]
Noble Gas. Metals have 1 or 2 Valence Electrons. Halogens have 7 Valence Electrons. Semi-Metals can have different amounts.
5 0
3 years ago
Read 2 more answers
Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -> 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how
bazaltina [42]

\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O

  • 13mol of O_2 reacts with 2mols of C_4H_10.
  • 7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}

\\ \tt\hookrightarrow \dfrac{400}{58}

\\ \tt\hookrightarrow 6.89mol

Now

Moles of O_2

\\ \tt\hookrightarrow 7.5(6.89)=51.6mol

Mass of O_2

\\ \tt\hookrightarrow 51.6(32)=1651.2g

4 0
2 years ago
During exercise your body's blood pressure increases as it cool down the body's blood pressure slowly returns to its normal stat
melamori03 [73]
Ur lungs i hope u get it
3 0
3 years ago
A particular graduated cylinder contains 24.0 mL Br2(liquid). The density of bromine at 25 degrees C is 3.12g/cm^3. Note that in
motikmotik

Answer:

2.82x10^{23}molecules

Explanation:

Hello.

In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:

\rho =\frac{m}{V}

m=\rho *V=3.12g/cm^3*24.0cm^3\\\\m=74.88gBr_2

Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:

n=74.88g*\frac{1mol}{159.82g} =0.469molBr_2

Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:

particles=0.469mol*\frac{6.022x10^{23}molecules}{1mol}\\ \\2.82x10^{23}molecules

Best regards.

4 0
3 years ago
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