Find the molecular mass of.

Chemistry

2 answers:

dem82 [27]3 years ago

7 0

Answer:

Explanation:

MOLECULAR MASS = ∑ the elements atomic mass from the periodic table

1st NaO

molecular mass = atomic mass of Na + Atomic mass of O

= ( 23 + 16 ) = 39 g/mol

2nd : AlCl3

M.m = atomic mass of Al + Atomic mass of 3Cl

( 27 + 3x35.5 )= 97 g/mole

3rd : Na3(SO4)

M.mass = atomic mass of 3 Na + atomic mass of S + atomic mass of 4 O

( 3x23) + 32 + (4 x 16) =165 g/mol

4th : Mg(OH)2

M.mass = atomic mass of Mg + atomic mass of 2 O + atomic mass of 2

= 24 + 2x16 + 2x1 = 58 g/mol

Margaret [11]3 years ago

3 0

Answer:

sodium oxide Nao
aluminum chloride Al2cl3
sodium sulphate Naso4
magnesium hydroxide Mgoh2

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3 years ago

The "correct" mass of the cylinder had been previously determined to be 27.20 grams. What was the percent error on his first wei

Paraphin [41]

Answer:

Percent error = - 8.1 %

Explanation:

Given data:

Actual mass = 27.20 g

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Percent error = ?

Solution:

Formula:

Percent error = theoretical value- actual value/ actual value × 100

Now we will put the values in formula.

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3 years ago

Methionine, ch3sch2ch2ch(nh2)co2h, is an amino acid found in proteins. what is the hybridization type of each carbon, oxygen, th

Lady_Fox [76]

Answer 1) To find the hybridization of carbon we need to draw the lewis structure first; which is attached in the answer.

So the formula for finding hybridization is
Lone pairs + Bonding pairs = hybridisation.

Here, in the molecule of methionine Carbon is bonded to all 4 atoms and has got no lone pairs so we will have;

0 + 4 = 4 which means it is $sp^{3}$ hybridized.

Answer 2) For oxygen we can see in the lewis structure that it is having 2 lone pairs and double bonded with carbon atom, also there is another oxygen atom with two lone pair but bonded with carbon and hydrogen at the end.

So, in both the cases we can calculate;

where 2 lone pairs are present
2 + 2 = 4 so, it will be $sp^{3}$ hybridized.

So, Oxygen is also $sp^{3}$ hybridized.

Answer 3) Nitrogen present in the methionine is bonded to carbon atom and hydrogen atoms and has only one lone pair on it.

So when we are substituting this in the formula we get 1 + 3 = 4;

which means 1 lone pair and 3 bond pairs so, it is also $sp^{3}$ hybridized.

Answer 4) Sulfur atom in methionine is bonded to two carbon atoms forming a linear structure with 2 lone pairs on it.

So, it has 2 lone pairs and 2 bond pairs,

hence the hybridization will be   $sp^{3}$ hybridized.

As, 2 + 2 = 4 which means it is   $sp^{3}$ hybridized.