1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marizza181 [45]
3 years ago
14

Find the molecular mass of.

Chemistry
2 answers:
dem82 [27]3 years ago
7 0

Answer:

Explanation:

MOLECULAR MASS = ∑ the elements atomic mass from the periodic table

1st NaO

molecular mass = atomic mass of Na + Atomic mass of O

                          = ( 23 + 16 ) = 39 g/mol

2nd : AlCl3

       M.m = atomic  mass of Al + Atomic mass of 3Cl

              (   27 +  3x35.5 )= 97 g/mole

3rd : Na3(SO4)

     M.mass =  atomic mass of 3 Na + atomic mass of S + atomic mass of 4 O

                    ( 3x23) +  32  + (4 x 16)  =165 g/mol

4th : Mg(OH)2

    M.mass = atomic mass of Mg + atomic mass of 2 O + atomic mass of 2

                 =   24 +   2x16 + 2x1 = 58 g/mol

   

Margaret [11]3 years ago
3 0

Answer:

  1. sodium oxide Nao
  2. aluminum chloride Al2cl3
  3. sodium sulphate Naso4
  4. <em>magnes</em><em>ium</em><em> </em><em>hydroxide</em><em> </em><em>Mgoh2</em>
You might be interested in
A sample of n2 effuses in 255 s. how long will the same size sample of cl2 take to effuse?
7nadin3 [17]
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:

R₁/R₂ = √(M₂/M₁)

Let 1 be N₂ while 2 be Cl₂

255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s

<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
4 0
3 years ago
When 20 grams of KCIO3, is dissolved in 100 grams of water, the solution can be
tia_tia [17]

Answer:

b. unsaturated .

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the definition of each type of solution:

- Supersaturated solution: comprises a large amount of solute at a temperature at which it will be able to crystalize upon standing.

- Unsaturated solution: is a solution in which a solvent is able to dissolve any more solute at a given temperature.

- Saturated solution can be defined as a solution in which a solvent is not capable of dissolving any more solute at a given temperature.

In such a way, since 20 grams of the solute are less than the solubility, we infer this is b. unsaturated, as 33.3 grams of solute can be further added to the 100 grams of water.

Regards!

6 0
3 years ago
Which of the following hazards does not apply for methanol?
AleksAgata [21]
Answer: the answer is C oxidizing
7 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
Are elements always transparent
Dmitry_Shevchenko [17]

No, the elements are not always transparent.

<u>Explanation:</u>

The elements become transparent when the light passes through those elements. Transparency is caused because of the transmission and the passing of the light waves through these elements.

But the metals do not become transparent even when the light waves pass through these metals. Metals do not become transparent because the refractive index in them is very big.

8 0
3 years ago
Other questions:
  • Which type of energy in gasoline is transformed into mechanical energy and a motorcycle engine
    12·1 answer
  • PLEASE HELP I WILL GIVE BRAINLY TO CORRECT ANSWER (after I finish test)
    11·1 answer
  • What does it mean to be recyclable? What are a few recyclable materials?
    9·2 answers
  • Are the strengths of the interactions between the particles in the solute and between the particles in the solvent before the so
    10·1 answer
  • What will for if sodium give away one electron ?
    6·1 answer
  • Suppose that NaCl is added to hexane (C6H14) instead of water. Which of the following intermolecular forces will exist in the sy
    11·2 answers
  • What are two effects of too much exposure to radiation?
    5·1 answer
  • Air is compressed in a piston–cylinder device from 90 kPa and 20°C to 650 kPa in a reversible isothermal process. Determine the
    7·1 answer
  • What type of heat transfer drives plate tectonics?
    12·1 answer
  • What causes water pollution?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!