Answer:
Chemical Formula:
For example- for every one mole of the compound PCl3 P C l 3 , it contains 3 moles of Chlorine atom and 1 mole of Phosphorus atom.
Explanation:
• Phosphorus trichloride (PCl3) contains three chlorine atoms and one phosphorus atoms.
Answer:
w = -531 kJ
1. Work was done by the system.
Explanation:
Step 1: Given data
- Heat gained by the system (q): 687 kJ (By convention, when the system absorbs heat, q > 0).
- Change in the internal energy of the system (ΔU°): 156 kJ
Step 2: Calculate the work done (w)
We will use the following expression.
ΔU° = q + w
w = ΔU° - q
w = 156 kJ - 687 kJ
w = -531 kJ
By convention, when w < 0, work is done by the system on the surroundings.
Answer:
<em>(H30+)= 1x10^-6 M</em>
Explanation:
Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:
1x 10-8 mol/L equals to1x10-8 M
(H3O+) x (OH-) = 1x10^-14
(H30+)x 1x 10^-8 =1x10^-14
(H30+)= 1x10^-14/1x 10^-8
<em>(H30+)= 1x10^-6 M</em>
First, we construct the reaction equation:
Na₂SO₃ + 2HCl → 2NaCl + SO₂ + H₂O
H₂SO₃ is formed as an intermediate but decomposes to water and SO₂ gas.
Answer: The last electron will be filled in first orbital of 3p sub-shell.
Explanation: Filling of electrons in orbitals is done by using Hund's Rule.
Hund's rule states that the electron will be singly occupied in the orbital of the sub-shell before any orbital is doubly occupied.
For filling up of the electrons in Sulfur atom having 16 electrons. First 10 electrons will completely fill according to Aufbau's Rule in 1s, 2s and 2p sub-shells and last 6 electrons are the valence electrons which will be filled in the order of 3s and then 3p.
3s sub-shell will be fully filled and the orbitals of 3p sub-shell will be first singly occupied and then pairing will take place. Hence, the last electron will be filled in the first orbital of 3p-sub-shell.
