Yes it is polluting the river with everything the manufaturing plant gives off such as the chemicals released in the air
Answer: Butane will effuse more quickly because it has a smaller molar mass
Explanation:
Molar mass of C4H10 = 58.123 g/mole
Molar mass of I2 = 253.808 g/mole
Q = 1.161 J/kg of heat is required to melt 99.9 g of solid acetic acid (HCH,CO2). Q = mL(Latent heat is the energy emitted or absorbed by a body while changing it state ). (Latent heat is the energy released or absorbed by a body while changing it state ).
<h3>How to fix?</h3>
Apply the equation Q = mL where:
Energy is Q. (J)
m = Mass (g)
L = Acetic acid's latent heat of fusion 192(J/g) = J/g
Q is equal to 0.099 kg times 11.73 kj/mol.
Q = 1.161J/kg.
<h3>What is latent heat, and what varieties are there?</h3>
Latent heat is the amount of energy that a substance experiencing a change in state, such as ice turning into water or water turning into steam, can absorb or release while maintaining a constant temperature and pressure. Types: The material exists in three states: solid, liquid, and gaseous.
<h3>What does "sensible heat" mean?</h3>
Heat that can actually be felt is considered to be sensible heat. Instead of the phase shifting, energy is what causes the temperature to vary as it moves from one system to another. For instance, it warms the water instead of melting the ice.
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1. The molar mass of the unknown gas obtained is 0.096 g/mol
2. The pressure of the oxygen gas in the tank is 1.524 atm
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>1. How to determine the molar mass of the gas </h3>
- Rate of unknown gas (R₁) = 11.1 mins
- Rate of H₂ (R₂) = 2.42 mins
- Molar mass of H₂ (M₂) = 2.02 g/mol
- Molar mass of unknown gas (M₁) =?
R₁/R₂ = √(M₂/M₁)
11.1 / 2.42 = √(2.02 / M₁)
Square both side
(11.1 / 2.42)² = 2.02 / M₁
Cross multiply
(11.1 / 2.42)² × M₁ = 2.02
Divide both side by (11.1 / 2.42)²
M₁ = 2.02 / (11.1 / 2.42)²
M₁ = 0.096 g/mol
<h3>2. How to determine the pressure of O₂</h3>
From the question given above, the following data were obtained:
- Volume (V) = 438 L
- Mass of O₂ = 0.885 kg = 885 g
- Molar mass of O₂ = 32 g/mol
- Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
- Temperature (T) = 21 °C = 21 + 273 = 294 K
- Gas constant (R) = 0.0821 atm.L/Kmol
The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side by V
P = nRT / V
P = (27.65625 × 0.0821 × 294) / 438
P = 1.524 atm
Learn more about Graham's law of diffusion:
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