The density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³
<h3>What is Density ?</h3>
Density is the measurement of how tightly a material is packed together.
It is defined as the mass per unit volume.
Given ;
- Mass = 23.5 g
- Volume = 13.5 cm³
Formula to calculate density ;
Density = mass / volume
=23.5 / 13.5 = 1.74 g/cm³
Hence, the density of magnesium will be 1.74 g/cm³ if 23.5 g of magnesium occupies 13.5 cm³.
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Answer:
The OH group
Explanation:
Benzhydrol contains OH hydroxyl group in its molecule while fluorene does not. At first glance, one would think that OH, which contributes to hydrogen bonding would causes melting point of benzhydrol to be higher than fluorene. <em>However, </em>the structure of benzhydrol, which is 2 benzene rings connected to center hydroxyl carbon (PhCOHPh), allows for each benzene rings in benzhydrol to rotate until both rings are perpendicular to minimize repulsive force. This prevents the molecule from stacking on each other due to its non flat shape, and thus, lowering its melting point in contrast to flat fluorene molecule.
Answer:
6.Given,
Final Velocity =60m/s
Initial Velocity= 0
Time=10 sec
A=?
A=Final Velocity- Initial Velocity/time
=60-0/10
=60/10
=6m/s ans.
Explanation:
Acceleration = Final Velocity - Initial Velocity/Time
By using this Formula we can calculate Acceleration.
Answer:
Technician B.
Explanation:
The claim of technician B that the PCM will add fuel if the IAT indicates that the incoming air temperature is cold is correct.
One
Balance the Equation.
This has been done for you or it is given. Anyway this step is finished, but it must always be done.
Two
Find the molar mass of C6H12O6
6C = 6 * 12 = 72
12H = 12*1 = 12
CO = 6 * 16 = 96
Mol Mass = 180 grams / mol
Three
Find the mols of C6H12O6
n = ???
Molar Mass = 180 grams / mol
given mass = 13.2 grams.
n = given mass / molar mass
n = 13.2 / 180
n = 0.07333333 mols.
Four
Find the mols CO2
1 mol C6H12O6 will produce 6 mols CO2
0.0733333 mols will produce x
1/0.073333 = 6/x Cross multiply
x = 0.073333 * 6
x = 0.4399 moles.
Five
Find the volume given the conditions for temperature and pressure are STP conditions.
PV = nRT
R = 0.082057
n = 0.43999
P = 1 atmosphere
T = 0 + 273 = 273
V = ???
1 * V = 0.43999 * 082057 * 273
V = 10.2 L
Answer: B
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