Answer:
B. it is a community of plants,animals and there physical surrounding.
Answer:
= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u
Answer:
did you mean moles? If so, answer is down below.
Explanation:
there are 0.106 moles of glucose in 19.1 g of glucose.
Answer:
Here's what I get
Explanation:
1. Names
I. CH₃-CH₂-COOH = 49. propanoic acid
II. CH₃-CH₂-OH = 46. ethanol
III. CH₃-COO-CH₂-CH₂-CH₃ = 47. propyl ethanoate
IV. H-O-CH₂-CH₂-CH₃ = 48. propan-1-ol
V. H-COO-CH₃ = 51. methyl methanoate
VI. CH₃-COOH = 50. ethanoic acid
2. Precursors
52. methyl propionate ⇒ methanol + propanoic acid
53. ethyl methanoate ⇒ ethanol + methanoic acid
