An exergonic reaction proceeds with net release of free energy.
An endergonic reaction absorbs free energy
Explanation:
The given data is as follows.
Solvent 1 = benzene, Solvent 2 = water
= 2.7,
= 100 mL
= 10 mL, weight of compound = 1 g
Extract = 3
Therefore, calculate the fraction remaining as follows.
![f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}](https://tex.z-dn.net/?f=f_%7Bn%7D%20%3D%20%5B1%20%2B%20K_%7Bp%7D%28%5Cfrac%7BV_%7BS_%7B2%7D%7D%7D%7BV_%7BS_%7B1%7D%7D%7D%29%5D%5E%7B-n%7D)
= ![[1 + 2.7(\frac{100}{10})]^{-3}](https://tex.z-dn.net/?f=%5B1%20%2B%202.7%28%5Cfrac%7B100%7D%7B10%7D%29%5D%5E%7B-3%7D)
= ![(28)^{-3}](https://tex.z-dn.net/?f=%2828%29%5E%7B-3%7D)
= ![4.55 \times 10^{-5}](https://tex.z-dn.net/?f=4.55%20%5Ctimes%2010%5E%7B-5%7D)
Hence, weight of compound to be extracted = weight of compound - fraction remaining
= 1 - ![4.55 \times 10^{-5}](https://tex.z-dn.net/?f=4.55%20%5Ctimes%2010%5E%7B-5%7D)
= 0.00001
or, = ![1 \times 10^{-5}](https://tex.z-dn.net/?f=1%20%5Ctimes%2010%5E%7B-5%7D)
Thus, we can conclude that weight of compound that could be extracted is
.
Answer:
9.8×10^-4...... is the answer