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Airida [17]
3 years ago
14

A series of six solutions was prepared at the given concentrations. Sample A B C D E F Concentration (mM) 50 100 150 200 300 400

Set of six cuvettes. The first is pale green, and the color becomes deeper green with each successive cuvette. The absorbance of each solution was then measured using a colorimeter. Sample A B C D E F Absorbance 0.25 0.50 0.75 1.00 1.50 2.00 What is the concentration of the solution with an absorbance of 1.50
Chemistry
1 answer:
ioda3 years ago
7 0

Answer:

300 mM

Explanation:

In order to solve this problem we need to calculate the line of best fit for those experimental values. The absorbance values go in the Y-axis while the concentration goes in the X-axis. We can calculate the linear fit using Microsoft Excel using the LINEST function (alternatively you can write the Y data in one column and X data in another one, then use that data to create a dispersion graph and finally add the line of best fit and its formula).

The <u>formula for the line of best fit for this set of data is</u>:

  • y = 0.005 * x

So now we <u>calculate the value of </u><u><em>x</em></u><u> when </u><u><em>y</em></u><u> is 1.50</u>:

  • 1.50 = 0.005 * x
  • x = 300 mM

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Consider the three equations below.
mash [69]

Answer:

Nuclear fusion plays an important role in making elements that are heavier than helium.

Explanation:

Nucleosynthesis is the process by which new atomic nuclei are created from pre-existing nucleons (protons and neutrons) and nuclei. According to current theories, the first nuclei were formed a few minutes after the Big Bang, through nuclear reactions in a process called Big Bang nucleosynthesis.

In order to synthesize a new element, there must be a change in the number of protons. We should remember that elements are known by the number of their protons as it represents their atomic number.

Elements heavier than helium are formed by nuclear nucleosynthesis in which nuclear fusion plays a very crucial role as typified by the equations shown in the question.

5 0
3 years ago
The car wit fastest acceleration is the tempest. it has an acceleration of 6.1 m/s. suppose the car accelerates from rest to a f
ziro4ka [17]

<u>Given:</u>

Initial velocity (v1) = 0 m/s

Final velocity (v2) = 30 m/s

Acceleration (a) = 6.1 m/s2

<u>To determine:</u>

The time (t) taken to reach the final speed

<u>Explanation:</u>

Use the relation:

Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)

t = (v2-v1)/a = 30-0/6.1 = 4.92 s

Ans: Time taken is around 4.9 s

3 0
3 years ago
Brainliest for correct answer please show all work
Korvikt [17]

Answer:

1) Na₃PO₄ + 3 KOH ➙ 3 NaOH + K₃PO₄

2) MgF₂ + Li₂CO₃➙ MgCO₃ + 2 LiF

3) P₄ + 3 O₂➙ 2 P₂O₃

Explanation:

To balance an equation, ensure that the number of atoms of each element is equal on both sides.

Reactants would be those on the left of the arrow while products are on the right of the arrow.

Balance O and H atoms last.

<u>Question 1:</u>

__Na₃PO₄ + __KOH ➙ __NaOH + __K₃PO₄

Reactants: 3Na, 1P, 1K, 5O, 1H

Products: 1Na, 1P, 3K, 5O, 1H

<em>Balance the number of Na:</em>

__Na₃PO₄ + __KOH ➙ 3 NaOH + __K₃PO₄

Reactants: 3Na, 1P, 1K, 5O, 1H

Products: 3Na, 1P, 3K, 7O, 3H

<em>Balance the number of K:</em>

__Na₃PO₄ + 3 KOH ➙ 3 NaOH + __K₃PO₄

Reactants: 3Na, 1P, 3K, 7O, 3H

Products: 3Na, 1P, 3K, 7O, 3H

<em>The equation is now balanced.</em>

<u>Question 2:</u>

__MgF₂ + __Li₂CO₃➙ __MgCO₃ + __LiF

Reactants: 1Mg, 2F, 2Li, 1C, 3O

Products: 1Mg, 1F, 1Li, 1C, 3O

<em>Balance</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>of</em><em> </em><em>L</em><em>i</em><em> </em><em>and</em><em> </em><em>F</em><em> </em><em>atoms</em><em>:</em>

__MgF₂ + __Li₂CO₃➙ __MgCO₃ + 2 LiF

Reactants: 1Mg, 2F, 2Li, 1C, 3O

Products: 1Mg, 2F, 2Li, 1C, 3O

<em>The</em><em> </em><em>equation</em><em> </em><em>is</em><em> </em><em>now</em><em> </em><em>balanced</em><em>.</em>

<u>Question 3:</u>

__P₄ + __O₂➙ __P₂O₃

Reactants: 4P, 2O

Products: 2P, 3O

<em>Balance</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>P</em><em> </em><em>atoms</em><em>:</em>

__P₄ + __O₂➙ 2 P₂O₃

Reactants: 4P, 2O

Products: 4P, 6O

<em>Balance</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>O</em><em> </em><em>atoms</em><em>:</em>

__P₄ + 3 O₂➙ 2 P₂O₃

Reactants: 4P, 6O

Products: 4P, 6O

<em>The</em><em> </em><em>equation</em><em> </em><em>is</em><em> </em><em>now</em><em> </em><em>balanced</em><em>.</em>

4 0
3 years ago
So I saw this question: If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + Na
Nataly_w [17]

mass of PbI₂ = 27.6606 g

<h3>Further explanation</h3>

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

4 0
3 years ago
If you flow a solution of Mg CO3-- in water over a Cation resin, what will be in the outlet stream leaving the bed
vodka [1.7K]

In a a cation-exchange resin, the outlet stream leaving the bed will contain H^{+} and CO_3 ^{2-}.

<h3>What is cation-exchange resin?</h3>
  • A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
  • It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
  • The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
  • cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
  • The most typical examples are water filtration and water softening.

To learn more about cation-exchange resin with the given link

brainly.com/question/21052225

#SPJ4

8 0
2 years ago
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