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MrMuchimi
3 years ago
8

The following graphs show the performance of two stocks over the first five months of the year.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer:

A. Stock XYZ shows the best performance. The scale of Stock ABC makes the graph appear to be rising more slowly.

Step-by-step explanation:

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Let the number be x.
9(1/4)+x=x/3+6
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Which expression is equivalent to ?
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Answer:

Step-by-step explanation:

\frac{(a^{2}b^{4}c)^{2}*(6a^{3}b)*(2c^{5})^{3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{2*2}b^{4*2}c^{2}6a^{3}b2^{3}c^{5*3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{4}b^{8}c^{2}6a^{3}b8c^{15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*8*a^{4+3}b^{8+1}c^{2+15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*2*a^{7}b^{9}c^{17}}{a^{6}b^{12}c{^3}}\\\\=\frac{12a^{7-6}c{17-3}}{b^{12-9}}\\\\=\frac{12a^{1}c^{14}}{b^{3}}\\\\=\frac{12ac^{14}}{b^{3}}

Hint:

x^{m}*x^{n}=x^{m+n}\\\frac{x^{m}}{x^{n}}=x^{m-n},m>n\\\frac{x^{m}}{x^{n}}=\frac{1}{x^{n-m}},n>m

5 0
3 years ago
on one day, 4 plumbers and 5 helpers earned $182. On another day, working the same number of hours and at the same rate of pay,
Elanso [62]
I hope this helps you



4plumbers +5helpers =182

5plumbers +6helpers =224



-24plumbers -30helpers =1092


25plumbers+30helpers =1120



1plumbers =28


4.28+5helpers =182



5helpers =70


1helpers=14
7 0
3 years ago
The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which
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The answer is the first one
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One of them is -6 the other one would be 6
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