1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
topjm [15]
3 years ago
6

The blue color of the sky results from the scattering of sunlight by air molecules. The blue light has a frequency of about 7.5

x 1014 Hz. What is the energy associated with this frequency?
Chemistry
2 answers:
EastWind [94]3 years ago
4 0

<u>Answer:</u> The energy associated with blue light is 49.65\times 10^{-20}J

<u>Explanation:</u>

To calculate the energy of the light for a given frequency, we use the equation given by Planck, which is:

E=h\nu

where,

E = energy of the light

h = Planck's constant = 6.62\times 10^{-34}Js

\nu = frequency of the light = 7.5\times 10^{14}s^{-1}

Putting values in above equation, we get:

E=6.62\times 10^{-34}Js\times 7.5\times 10^{14}s^{-1}=49.65\times 10^{-20}J

Hence, the energy associated with blue light is 49.65\times 10^{-20}J

serious [3.7K]3 years ago
3 0
A) c = 3 x 10^8 m/s 
<span>f = 7.15 x 10^14 Hz </span>
<span>c = λ x f (=) λ = 3 x 10^8 / 7.15 x 10^14 = 4.19 x 10^-7 m = 419.6 nm </span>

<span>B) E = h  f </span>
<span>H = Planck's constant = 6.63 x 10^-34 J/s </span>
<span>E = 6.63 x 10^-34 x 7.15 x 10^14 = 4.74 x 10^-19 J</span>
You might be interested in
Write a balanced half-reaction for the oxidation of gaseous nitric oxide NO to nitrate ion NO−3 in acidic aqueous solution. Be s
crimeas [40]

Answer:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the initial version of the half-reaction as follows:

NO\rightarrow NO_3^-

Now, we assign the oxidation numbers to both nitrogen atoms:

N^{2+}O\rightarrow N^{5+}O_3^-

It means three electrons are carried, two water molecules are needed on the left side in order to balance the oxygen atoms and consequently four hydronium ions to balance hydrogen atoms in acidic media:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Regards!

3 0
3 years ago
Fountain
iren2701 [21]

Answer:

4104 Coulombs

Explanation:

charge = time(sec) *current

25*60 =1500+20=1520

2.7A * 1520 sec =4104

4104 C

3 0
3 years ago
Which are balanced plus if they aren’t please correct them
Veronika [31]

b,f,h are already balanced

7 0
3 years ago
Help me pleaseee. ty if you dooo :))
Lina20 [59]

\huge \fcolorbox{black}{red}{♛answer♛}

Hydrogen Fluoride / HF

\huge\sf\underline{\underline{\red{❥︎ Thanks}}}

3 0
2 years ago
Rank the following elements by electron affinity, from most positive to most negative EA value.
LenKa [72]

Answer:

Explanation:

Bromine >Tellurium > Phosphorus > Helium > Sodium

Electron affinity of Bromine , Tellurium , Phosphorus are positive , of helium is zero and of sodium is negative .

3 0
3 years ago
Other questions:
  • What is the product when NH3 decomposes
    11·1 answer
  • What is the electron configuration of an element with an atomic number of 9?
    13·1 answer
  • Cooks use baking soda to make cakes light and fluffy. You might have used baking soda yourself. Baking soda is NaHCO3. A 0.1 M s
    14·1 answer
  • Which option describes a similarity and a difference between isotopes of an element?
    9·1 answer
  • What is warmer during the day: land or sea/ocean?
    11·2 answers
  • I NEED HELP PLEASE !!!!!
    14·2 answers
  • How many grams of KOH are required to prepare 500. mL of 0.450 KOH solution?
    5·1 answer
  • The volume of a ball was measured at 500.0 cm?, and its mass was measured to be 404.2 g.
    6·1 answer
  • A hydrocarbon contains C,H, and F atoms. A 5.43 g sample of this hydrocarbon was analyzed and the mass of 2.35 g of carbon and 0
    13·1 answer
  • Some one have a full conversation with me I am so bored
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!