Answer:
The number ratio is 4:7
Explanation:
Step 1: Data given
Compound 1 has 50.48 % oxygen
Compound 2 has 36.81 % oxygen
Molar mass oxygen = 16 g/mol
Molar mass manganese = 54.94 g/mol
Step 2: Calculate % manganes
Compound 1: 100 - 50.48 = 49.52 %
Compound 2: 100 - 36.81 = 63.19 %
Step 3: Calculate mass
Suppose mass of compounds = 100 grams
Compound 1:
50.48 % O = 50.48 grams
49.52 % Mn = 49.52 grams
Compound 2:
36.81 % O = 36.81 grams
63.19 % Mn = 63.19 grams
Step 4: Calculate moles
Compound 1
Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles
Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles
Compound 2
Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles
Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles
Step 5: calculate mol ratio
We will divide by the smallest amount of moles
Compound 1
O: 3.155/0.9013 = 3.5
Mn: 0.9013 / 0.9013 = 1
Mn2O7
Compound 2
O: 2.301 / 1.150 = 2
Mn: 1.150 / 1.150 = 1
MnO2
The number ratio is 2:3.5 or 4:7
Answer:
1 mole of iron =6.023×10^23 particles
1 particles of iron=1/6.023×10^23 mole
7.46×10^25 particles =1/6.023×10^23×7.46×10^25
=1.238×10^48 mole is a required answer.
From what I experienced I gets really loud with the smell but other than that nothing happens just the smell gets stronger
Explanation:
The atomic spectrum is more like the transitions of electrons among electronic energy levels in an isolated atom. Atomic spectrum is mainly affected by interaction of the transitioning electrons between the nuclei spins and between the other electrons in the same atom.
However, molecular spectrum involve transition of electrons in molecules with two and more atoms(it can be in the same or different). Also, the valence electrons are now in different orbitals than that of the atomic orbitals and the orbital structure has changed the electronic transitions are different
