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enyata [817]
3 years ago
14

What is the mass of hydrogen in 5.5 mol of Ca(OH)2?​

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

12*2*6.022*10^23. Atoms of hydrogen.

Explanation:

First of all if u know that 1 molecule of calcium hydroxide contain 2 hydrogen atom and 1 mole of calcium hydroxide contain 6.022*10^23 molecules of calcium hydroxide.

Hence 1 mole of calcium hydroxide contain 2*6.022*10^23 atom of hydrogen.

So 12 mole of calcium hydroxide contain =12*2*6.022*10^23. Atoms of hydrogen.

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A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
Maurinko [17]
<h3>Answer:</h3>

P₂ = 0.67 atm

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Gas Laws</u>

Boyle's Law: P₁V₁ = P₂V₂

  • P₁ is pressure 1
  • V₁ is volume 1
  • P₂ is pressure 2
  • V₂ is volume 2
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

<u>Step 2: Solve</u>

  1. Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)
  2. [Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)
  3. [Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂
  4. [Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>

0.673333 atm ≈ 0.67 atm

4 0
3 years ago
Sylvanite is a mineral that contains 28.0% gold by mass. How much sylvanite would you need to dig up to obtain 73.0 g of gold?
Scorpion4ik [409]

You would have to dig up 261 g of sylvanite.

Mass of sylvanite = 73.0 g Au × (100 g sylvanite/28.0 g Au) = <em>261 g</em> sylvanite.


3 0
3 years ago
Use these images to identify each state of matter.
rewona [7]

Answer:

Just too clarify its actually

A: gas

B: solid

C: liquid

4 0
3 years ago
Select the letter of a category on which you should focus when proofreading.
oee [108]
B. Who, what, when, where, why, and how. Those are the most important and key componants in a story.
8 0
3 years ago
An unknown substance has a density of 56 g/cm3. Its volume is 3.5 cm.
postnew [5]

Answer:

<h3>The answer is 196 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 56 × 3.5

We have the final answer as

<h3>196 g</h3>

Hope this helps you

3 0
3 years ago
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