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charle [14.2K]
3 years ago
14

Plz help ASAP i will give brainlists

Chemistry
1 answer:
Law Incorporation [45]3 years ago
6 0
The correct answer is C!
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What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL
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Density is weight by volume.   

First.  If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL

1L=1000ml

\frac{1L}{1000mL}

(382.14mL)( \frac{1L}{1000mL})= \frac{(382.14mL)(L)}{1000mL} =\frac{382.14L}{1000}=0.38214L

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4 0
4 years ago
How many moles of Cs are contained in 3 moles of Cs3PO4?
Alenkinab [10]

Answer:

\boxed {\boxed {\sf 9 \ moles \ Cs}}

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs

3 moles of cesium phosphate contains <u>9 moles of cesium.</u>

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3 years ago
In a chemical reaction, [_____] are the substances present after the reaction.
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Answer:

Products

Explanation:

5 0
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