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GREYUIT [131]
2 years ago
8

Help meeeeeeeeeeeeeee ​

Chemistry
1 answer:
lesya [120]2 years ago
8 0

AMSWER :

CHEMICAL FORMULA :

• WATER - H2O

• CARBONDIOXIDE - CO2

• SODIUM HYDROXIDE - NaOH

• SULPHURIC ACID - H2SO4

• SODIUM CHLORIDE - NaCI

• SODIUM BICARBONATE - NaCHO3

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How long would it take a current of 10A to deposit 6.36g of copper during the electrolysis of copper (ll) tetraoxosulphate VI so
zhuklara [117]

It take 0.54 hours to deposit 6.36g of copper

<h3>Further explanation</h3>

Faraday's Law I

"The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis

W = e.i.t / 96500

\tt \large {\boxed {\bold {W \: = \: \dfrac {e \times  i \: x \: t} {96500}}}}

e = equivalent = Ar / valence

i = current, A

t = time, s

W=6.36 g

e = 63.5 : 2 =31.75

i = 10 A

\tt t=\dfrac{W\times 96500}{e.i}\\\\t=\dfrac{6.36\times 96500}{31.75\times 10 }\\\\t=1933.04~s\approx 0.54~hours

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The rotation of the Earth.

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There are several ways to model a compound. One type
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Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

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Donde la constante de equilibrio, Ka, es

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Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

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Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

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5.35x10⁻⁵M / 0.1732M * 100

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