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3 years ago

According to the plate tectonics model, what layers form earth's rigid, mobile plates

Physics

1 answer:

Mazyrski [523]3 years ago

8 0

Crust & Upper Mantle

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A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. the cylinder is suspended several meters

emmainna [20.7K]

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3 years ago

Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency res

aleksandr82 [10.1K]

Answer:

The percentage change in frequency is 10%.

Explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

$\Delta f=\Delta A\times R$

Put the value into the formula

$\Delta f=\dfrac{1}{10}\times10$

$\Delta f=1\ Hz$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f_{r}=R-\Delta f$

Put the value into the formula

$f_{r}=10-1$

$f_{r}=9\ Hz$

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

$f=\dfrac{10-9}{10}$

$f=10\%$

Hence, The percentage change in frequency is 10%.

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4 years ago

A block of mass 10.1kg rests on a slope an angle of 43.9∘ relative to the horizontal. What is the size of the force parallel to

Julli [10]

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3 years ago

The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b

bagirrra123 [75]

To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.

By definition the torque is defined as

$\tau = F*r$

Where,

$\tau = Torque$

F = Force

r = Radius

For our values we have:

$\tau = F*r$

$\tau = (1.75*10^3)(2.8*10^{-2})$

$\tau = 49Nm$

Consequently the calculation of the moment of inertia would then be given by the relationship

$\tau = I\alpha$

$I=\frac{\tau}{\alpha}$

Replacing with our values

$I = \frac{49}{150}$

$I = 0.322Kg.m^2$

The moment of inertia of the boxer's forearm $0.322Kg.m^2$

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3 years ago

Answer my question please and i will mark you as brainliest i promise

stiks02 [169]

Answer:

From point A to point B there is 15sec and from point C to point D there is 9sec.

Explanation:

6 0

4 years ago

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